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Harrizon [31]
2 years ago
7

What conclusion about the bacteria domain could be made from the phylogenetic tree below? the first branch of the phylogenetic t

ree holds the species of the bacteria division. It contains thermotoga bacteria, green non sulfur bacteria, cyanobacteria, gram positive bacteria, and purple bacteria. The second branch of the phylogenetic tree holds species of the eukarya. It contains diplomonads, microsporidia, trichomonads, flagellates, entamoeba, slime molds, ciliates, plants, animals, and fungi. The last branch of the phylogenetic tree starts at the beginning of eukarya line and holds the species of the archaea division. It contains thermococcus, pyrodictium, thermoproteus, methanobacterium, and extreme halophiles. Plants and animals evolved from the bacteria domain. Bacteria and eukarya are more similar than archaea and eukarya. Bacteria and archaea have similar evolutionary traits. Eukarya and bacteria developed on the same evolutionary line.
SAT
1 answer:
irga5000 [103]2 years ago
3 0

The conclusion about the bacteria domain could be made from the given phylogenetic tree is; Eukarya has similar evolutionary traits to Archaea.

<h3>What is a phylogenic tree?</h3>

From the question, the ultimate branch of the phylogenetic tree starts with the line of Eukarya and then possesses the species of the Archaea division that comprises those prokaryotic species, which thrives in extremely tough environmental scenarios.  

Now, as the last branch possesses species of two domains namely Eukarya and Archaea and it starts with Eukarya and afterward holds the species of Archaea, and that tells us that both Eukarya and Archaea are associated genetically.  

In conclusion, what we can say about the bacteria domain is that Eukarya has similar evolutionary traits to Archaea.

Read more about Phylogenic tree at; brainly.com/question/2189834

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Consider the unbalanced reaction,

H₂ + N₂   ===>   NH₃

Balance it to get

3 H₂ + N₂   ===>   2 NH₃

This tells you that for every 3 moles of H₂ and 1 mole of N₂ among the reactants, 2 moles of NH₃ are produced.

Look up the molar masses of each component element:

• H : 1.008 g/mol     ===>   H₂ : 2.016 g/mol

• N : 14.007 g/mol     ===>   N₂ : 28.014 g/mol

• NH₃ : 17.031 g/mol

Convert the given mass to moles for each reactant:

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(5.22 kg) × (1000 g/kg) × (1/2.016 mol/g) ≈ 2589.29 mol

• N₂ :

(31.5 kg) × (1000 g/kg) × (1/28.014 mol/g) ≈ 1124.44 mol

Now,

(2589.29 mol H₂) : (1124.44 mol N₂) ≈ (2.30 mol H₂) : (1 mol N₂)

so that the amount of N₂ consumed is

(2589.29 mol H₂) × (1 mol N₂) / (3 mol H₂) ≈ 863.095 mol N₂

leaving an excess of about 261.343 mol N₂, and producing

(2589.29 mol H₂) × (2 mol NH₃) / (3 mol H₂) ≈ 1726.19 mol NH₃

Convert this to a mass :

(1726.19 mol) × (17.031 g/mol) × (1/1000 kg/g) ≈ 29.3987 kg

So, up to 29.4 kg of NH₃ can be synthesized.

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