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PSYCHO15rus [73]
3 years ago
13

Kkkkkkkkkk HELPPPP RNNNNNNNN

Mathematics
1 answer:
k0ka [10]3 years ago
7 0

Answer:

c

Step-by-step explanation:

every vertical line must doesn't have any accident with graph like the graph C.

You might be interested in
The sum of three positive consecutive integers is 66. what are the three integers​
vredina [299]

Answer: 21, 22, 23

Step-by-step explanation:

you divide 66 with 3, that equals 22, then you have three 22. Then you have to take 1 from one of the 22s and give it to the other one, making it 21, 22 and 23

7 0
4 years ago
1) Which of the following does not show the Commutative Property of Addition ?
Luda [366]

Answer:

I think it would be c.ab=ba but im not 100% sure

Step-by-step explanation:

4 0
3 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
Tell whether the angles are adjacent or vertical. Then find the value of x.
krok68 [10]

Answer : The angles are vertical angles and the value of x is 25^o

Step-by-step explanation :

Adjacent angles : It is defined as the two angles that have the common arm and common vertex.

Vertical angles : It is defined as the two lines intersect each other and form angles. The opposite angles are known as vertically opposite angles.

And we know that the vertically opposite angles are equal.

In the given image, the angles are vertical angles and vertically opposite angles are equal.

So,

(4x-25)^o=75^o

4x-25^o=75^o

4x=75^o+25^o

4x=100^o

x=\frac{100^o}{4}

x=25^o

Therefore, the angles are vertical angles and the value of x is 25^o

6 0
3 years ago
How do I work this out
Yuri [45]

Answer:

the total number of blocks is 69

Step-by-step explanation:

the way you can find this is by counting all the outside blocks on the closest side (23) and multiplying it by the the width of the blocks on the right side (3)

6 0
3 years ago
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