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trasher [3.6K]
3 years ago
14

Solve this system using any method (substition elimination) Thank you!!!

Mathematics
1 answer:
Nady [450]3 years ago
8 0

Answer:

look at the picture shown

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Which description represents the expression 4 - r/3
sergey [27]
Hello,


The answer to this problem is, C.

4 minus the quotient of a number and 3



Hope this helps!
8 0
3 years ago
Hello help me please​
laila [671]

Answer:

7

Step-by-step explanation: it intersects on the y-axis

5 0
2 years ago
Read 2 more answers
FIRST ON TO ANSWER GETS BRAINIEST!!!!!! system can be as small as two atoms colliding, as large as the entire universe True Fals
8090 [49]

Answer:

True

Step-by-step explanation:

system can be as small as two atoms colliding, as large as the entire universe.

System : it is the quantity of matter that is bounded by a boundary, of some fixed matter, which is under observation for changes.

We can fix anything to everything as our system, we want to observe and work on it.

The whole universe can also be considered as a system, which is isolated.

This is because, mass is always conserved and the entropy of this system(universe) is always increasing as there are a number of irreversible processes taking place in the universe.

Two atoms colliding can also make upto a system, if we want to observe the changes in the thermodynamical properties taking place in that system.

3 0
3 years ago
An arc subtends a central angle measuring 2pi/3
RoseWind [281]

Answer:

1/3

Step-by-step explanation:

We know that angle subtended by whole circumference is 2\pi.

If r is the radius then Length of whole circumference is 2\pi r

2\pi radian has 2\pi r  length

dividing  both side by 2\pi we have

2\pi /2\pi  = 2\pi r/2\pi  \ circumference

1 radian has r length  

1 radian = r length      equation a

=> since we have to find value of circumference for 2\pi /3 we

multiply both side of equation a with 2\pi /3.

2\pi /3 \radian = r* 2\pi /3 \circumference

therefore, length of required arc is 2\pi r/3

________________________________________________

we have to find how much is this as fraction of total  circumference of circle

fraction of circumference = value of arc length / total length of circumference

fraction of circumference = =>(2\pi r/3) / 2\pi r\\=> 1/3

Thus, the given arc is 1/3 of circumference of circle.

8 0
3 years ago
A hemispherical tank is filled with water and has a diameter of 4 feet. If water weighs 62.4 pounds per cubic foot, what is the
yulyashka [42]

The total weight of the water in a full tank, to the nearest pound is 1056 pounds, if water filled with water in the 4 diameter hemispherical tank and weighs 62.4 pounds per cubic foot.

Step-by-step explanation:

         The given is,

              A hemispherical tank is filled with water and has a diameter of 4 feet.

              Water weighs 62.4 pounds per cubic foot

Step:1

             Formula to weight of water is,

                          = Volume of water tank × weight of water per foot......(1)

Step:2

             Formula to find volume of the tank is,

                        V = \frac{2}{3} \pi  r^{3}...................................(2)

             From given, r = Radius of Hemisphere

                        r = \frac{d}{2}

                           = \frac{4}{2}

                         r = 2 foot    

            From equation (2),        

                            = \frac{2}{3} × \pi × 2^{3}

                            = 16.755 cubic foot

Step:3

            From equation (1),

                            = 16.775 × 62.4              (∵ Water weighs 62.4 pounds per cubic foot )

                            = 1045.52 pounds        ( ∵ foot^{3} × \frac{pounds}{foot^{3}} = pounds )

                            ≅ 1046 pounds

            Weight of water in tank = 1046 pounds

Result:

           The total weight of the water in a full tank, to the nearest pound is 1056 pounds, if a hemispherical tank is filled with water and it has 4 feet diameter and water weighs 62.4 pounds per cubic foot.

7 0
3 years ago
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