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andreev551 [17]
2 years ago
15

Element X decays radioactively with a half life of 9 minutes. If there are 890 grams of Element X, how long, to the nearest tent

h of a minute, would it take the element to decay to 238 grams?
Mathematics
1 answer:
elena-s [515]2 years ago
3 0

Answer:

13.18651685

13.9

Explain:

890-238=652
652/890=0.7325842697 (Find out the percentage)

We know that 1 gram of Element X will be fully decayed in 18 minutes and half of it in 9 minutes.

0.7325842697x18=13.18651685

As you see 18/13.18651685 will equal to 18 (not exactly since it is rounded)

And of course we need to round it to nearest tenth. So the answer would be 13.9!

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What is the greatest number of teams can be formed that have the same amount of boys and girls on each team if they have 54 girl
elena55 [62]

The greatest number of teams can be formed that have the same amount of boys and girls on each team is 6

<em><u>Solution:</u></em>

Given that there are 54 girls and 84 boys

We have to find the greatest number of teams can be formed that have the same amount of boys and girls on each team

So we have to find the greatest common factor of 54 and 84

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

<em><u>Let us find the factors of 54 and 84</u></em>

The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54

The factors of 84 are: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

In the above factors list, 6 is the greatest common factor

Then the greatest common factor is 6

So the greatest number of teams can be formed that have the same amount of boys and girls on each team is 6

7 0
4 years ago
A school P is 16km due west of a school Q. what is the bearing of Q from P​
Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find  the bearing of Q from P​

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of QP------------------>Q

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of  School Q from P is 16Km due east of school P

7 0
3 years ago
8/10 is iqual to 4/5
yan [13]
Yes, that is correct because if you want to reduce it you divide 8 by 2 and 10 by 2 and you get 4/5
5 0
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(C) jasmyne is the one with the proportinal relationship

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Jackson makes 7 calls each day after 36 days how many calls will Jackson make?
oksian1 [2.3K]

Answer:

352 calls

Step-by-step explanation:

Each day he makes 7 calls and 36 days have gone by so you'll multiply 36 and 7.

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