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morpeh [17]
4 years ago
7

1 .Is the product of two rational numbers irrational or rational? First, make a hypothesis by multiplying two rational numbers.

Then, use variables such as x=a/b and y=c/d and the closure property of integers to prove your hypothesis.
2.What do you think the product of a nonzero rational number and an irrational number is? Is it rational or irrational? Make use of variables, the closure property of integers, and possibly a proof by contradiction to prove your hypothesis.

3.Why do we have to specify that the rational number must be nonzero when we determine what the product of a nonzero rational number and irrational number is? If the rational number were 0, would it give us the same result we found in part B?


I WILL GIVE BRAINLIEST ANSWER TO SOMEONE WHO ACTUALLY ANSWER THE QUESTION THE RIGHT WAY
Mathematics
1 answer:
horsena [70]4 years ago
6 0

Answer:

irrational lol 2 whole years

later

Step-by-step explanation:

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Is 192 rational , why is it?
Oduvanchick [21]

Answer: 192 IS IRRATIONAL. I HOPE THIS ANSWER HELPS.

Step-by-step explanation:

It is an irrational number if it is not a perfect square. Since 192 is not a perfect square, it is an irrational number. This means that the answer to "the square root of 192?" will have an infinite number of decimals. The decimals will not terminate and you cannot make it into an exact fraction.

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3 years ago
Find the equation of the line that passes through the points (6,14) and is parallel to y=-4/3x-1
Yuri [45]

Answer:

y= -4/3 + 22

Step-by-step explanation:

y= -4/3x -1

14 = -4/3 (6) + b

14= -8 + b

22= b

8 0
3 years ago
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lora16 [44]

Answer:

Arithmetic

Step-by-step explanation:

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Where’s the table? Then I can help u.
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Read 2 more answers
Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then
Debora [2.8K]
To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form f(x)=x^2+bx+c it vertex (h,k) is given by h= \frac{-b}{2a}, k=f(h).
We can infet from our parabola that a=2 and b=-12. So lets replace those values in our formula:
h= \frac{-b}{2a}
h= \frac{-(-12)}{2(2)}
h= \frac{12}{4}
h=3
k=f(h)=2(3)^2-12(3)+19
k=2(9)-36+19
k=18-17
k=1
The vertex (h,k) of our parabola is (3,1)

Now to find our second point, we are going to evaluate our parabola at x=0
f(0)=2(0)^2-12(0)+19
f(0)=0+0+19
f(0)=19
Our second point is (0,19)

We can conclude that we can graph the parabola f(x)=2x^2-12x+19 using its vertex (3,1) and the point (0,19) as follows: 

7 0
3 years ago
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