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2 years ago

Guys can u help me asap ?? i need explaination aloong the answer

Mathematics

1 answer:

Alisiya [41]2 years ago

5 0

Answer:

5225 x 5/100 = 261.25

5225 - 261.25 = 4963.75

Step-by-step explanation:

We know that % means a 100 so if they say they allowed a 5% discount then that would be 5/100.

You will take the fraction and multiple it with the original price. It will then give you the discount price, you will then need to subtract the discounted amount from the original sale price which is 5225. Then you will get your final answer.

;-)

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Find the slope of the line passing through each pair of points.

Klio2033 [76]

Answer:

you have to use the slope equation, which is (y2-y1) / (x2-x1)

3. (5-0)/(1 -(-8))

5/1+8

5/9

4. (3-3)/(-4 -8)

0/-12

the slope is 0

6. (-2-8)/(1-0.5)

-10/0.5

-20

7. (7-(-1))/ (4-4)

7+1/0

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the slope is undefined

5 0

2 years ago

Reduce the following fractions to lowest terms: 36/39

liubo4ka [24]

Answer:

12/13

Step-by-step explanation:

36/39

Divide by 3

12/13

3 0

1 year ago

A/-8+15>23 isn't this weird to you guys too

yanalaym [24]

Let's solve your inequality step-by-step.

a − 8 + 15 > 23

Step 1: Simplify both sides of the inequality.

−1/8a + 15 > 23

Step 2: Subtract 15 from both sides.

−1/8a + 15 − 15 > 23 − 15

−1/8a > 8

Step 3: Multiply both sides by 8/(-1).

(8/−1) * (−1/8a) > (8/−1) * (8)

a < −64

Therefore, the answer is a < -64! I hope this helped! :)

4 0

2 years ago

kfc has 11 more then twice as many customers as when they started selling food . kfc now has 73 customers . how may did they hav

matrenka [14]

Answer:

<h2>73 - 11 equals 62. THE ANSWER IS 31.</h2><h2>PLEASE ADD AS BRAINEST.</h2>

Step-by-step explanation:

3 0

2 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

Solution:

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

2 years ago