Is it possible to identify The exact values of all the original service times? A. Yes. The data values in each class are equal t
o the corresponding class midpoint. P. No. The frequency distribution tells nothing about the data values that fall below the lowest class limit or above the highest class limit. C no. The data values in each class could take on any value between the class limits, inclusive. D. Yes. The data values in each class are spread evenly across the full length of the class.
Y = 40 Since, 1st year = 200 2nd year= 200 + 40 =240 3rd year = 240 + 40 = 280 4th year = 280 + 40 = 320 5th year = 320 + 40 =360 6th year = 360 + 40 = 400. So, basically all you have to do is add 40! Therefore, the answer is y = 40 Hope this helped! :)