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a_sh-v [17]
2 years ago
12

Is it possible to identify The exact values of all the original service times? A. Yes. The data values in each class are equal t

o the corresponding class midpoint. P. No. The frequency distribution tells nothing about the data values that fall below the lowest class limit or above the highest class limit. C no. The data values in each class could take on any value between the class limits, inclusive. D. Yes. The data values in each class are spread evenly across the full length of the class.
Mathematics
2 answers:
kakasveta [241]2 years ago
8 0

Answer:

C.

Step-by-step explanation:

The answer to your question would be C. No, the data values in each class could take on any value between the class limits, inclusive.


I hope it helps! Have a great day!

Muffin~

tia_tia [17]2 years ago
5 0

Answer:

C.) No. The data values in each class could take on any value between the class limits, inclusive.

I hope I helped! ^-^

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A sweet factory produces 5 different chocolate bars. the different flavors are always produced in the same proportions, for ever
IRISSAK [1]

a. There are 933 chocolate bars

b. There are 1200 chocolate bars

c. There are 1580 chocolate bars

<h3>How to calculate the number of chocolate bars</h3>

Since there are 5 different flavors,

let

  • x = orange flavored bars,
  • y = coconut flavored bars,
  • z = coffee flavored bars,
  • a = strawberry flavored bars and
  • b = honeycomb flavored bars and
  • X = total number of bars

Since the different flavors are always produced in the same proportions, for every 4 coconut flavored bars 5 honeycomb 6 orange 1 coffee and 4 strawberry

So, the ratio of their proportions are x:y:z:a:b = 6:4:2:1:5

So, the total ratio is T = 6 + 4 + 1 + 4 + 5 = 20

<h3>a. What is the total number of chocolate bars if there are 280 orange flavored bars?</h3>

Since we have 6 orange flavored bars, the ratio of orange flavored bars to total is 6/20

So, the amount of orange flavored bars is x = 6/20 × X

Making X subject of the formula, we have

X = 20x/6

So, if there are 280 orange bars, there will be

X = 20x/6

X = 20 × 280/6

X = 5600/6

X = 933.33

X ≅ 933 chocolate bars

So, there are 933 chocolate bars

<h3>b. What is the total number of chocolate bars if there are 960 coconut flavored bars?</h3>

Since we have 4 coconut flavored bars, the ratio of coconut flavored bars to total is 4/20

So, the amount of coconut flavored bars is y = 4/20 × X

Making X subject of the formula, we have

X = 20y/4

So, if there are 960 coconut flavored bars, there will be

X = 20y/6

X = 20 × 960/4

X = 5 × 240

X = 1200 chocolate bars

So, there are 1200 chocolate bars

<h3>c. What is the total number of chocolate bars if there are 79 coffee flavored bars?</h3>

Since we have 1 coffee flavored bars, the ratio of coffee flavored bars to total is 1/20

So, the amount of coconut flavored bars is z = 1/20 × X

Making X subject of the formula, we have

X = 20z

So, if there are 79 coffee flavored bars, there will be

X = 20z

X = 20 × 79

X = 1580 chocolate bars

So, there are 1580 chocolate bars

Learn more about ratio here:

brainly.com/question/1127546

#SPJ1

7 0
1 year ago
The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).
lesantik [10]

Answer:

(a).

S_{n} =  \frac{n}{2} (4n + 20) \\  \\S _{n - 1} =  \frac{(n - 1)}{2} (4n - 4 + 20) \\  \\ S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16) \\  \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2}  \\   \\  { \boxed{S _{n - 1} =  {2 {n}^{2} + 6n - 8}}} \\

(b).

from general equation:

S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16)

first term is 4n

common difference:

16 =  \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d =  \frac{16}{n - 2}

8 0
3 years ago
The sum of 10 and twice a number<br> (an equation)
Gekata [30.6K]

Answer:

10+2x= the sum (anything could be put here)

Step-by-step explanation:

Well sum is automatically addition

Doubleing a number is basically multiplying it by 2

so

10+2x= whatever youw ant to put here

8 0
2 years ago
Find the range of the data set 247, 366, 785, 997
nasty-shy [4]
Range is the difference between the lowest and highest values. 
997- 247= 750
8 0
3 years ago
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True or false "No rectangle is a rhombus?"
alukav5142 [94]
False.
Rhombuses may be rectangles<span>, as long as the shape is a square. </span><span>Every square is a </span>rhombus <span>if all its angles equal 90 degrees.</span>
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