Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24 or 1/2 (reduced)
However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23
Now multiply those possibilities:
1/2 x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row. 11/46 is the answer.
The answer to that is -15-36 hope that helps you with your problem.
30+45=75
75/5=15
15 seeds in each row!!
Hope i helped:)
Answer:
1
Step-by-step explanation:
m/8n > 4/8(1/2) ( since its 1/2 all you need to do is change the fraction to whole number which is 1/2 = 0.5)
The given will become 4/4 then simplest form is 1
Answer:
4851 ways
Step-by-step explanation:
The fish have 3 choices. They can make it above, below, or though the pipe. Keep in mind there are 100 fish total:
group 1 + group 2 + group 3 = 100
If we keep group 3 (the fish that swim below the pipe) constant, say 1, and increment the other two (group 2 starting off at 1) we find 98 possibilities.
98 + 1 + 1 = 100,
97 + 2 + 1 = 100,
96 + 3 + 1 = 100
. . . 98 possibilities
Now we take group 1 as one greater (1 + 1 = 2) and then start incrementing group 2 starting from 1 as done before. So 97 + 2 + 1 = 100. Followed by 96 + 3 + 1, 95 + 4 + 1...97 possibilities
If we continue this pattern, we have 98 + 97 + 96... + 1 total possibilities to partition this school of fish.
98 + 97 + 96... + 1,
Sum = n(n + 1)/2 = 98(98 + 1)/2 = 98(99)/2 = 4851
