A(-4, 2) and B(3, -2).
I will do number 2.
Let d(A, B) = distance between the two points.
d(A, B) = sqrt{(3 -(-4))^2 + (-2-2)^2}
d(A, B) = sqrt{(3 + 4))^2 + (-2-2)^2}
d(A, B) = sqrt{(7)^2 + (-4)^2}
d(A, B) = sqrt{49 + 16}
d(A, B) = sqrt{65}
Done!
I don’t know what the answer is I wish I could help
Answer:
The required range is 237.5 to 275.
Step-by-step explanation:
Consider the provided information.
The average cholesterol of the target population is 200 mg and they have a standard deviation of 25 mg.
The the value of μ = 200 and the 
The company wished to test a sample of people who fall between 1.5 and 3 z-scores above the mean.
Let the value of z is 1.5.
Now use the z score formula: 
Substitute the respective values in the above formula.



Now let the value of z is 3.
Substitute the respective values in the z score formula.



Hence, the required range is 237.5 to 275.
Answer:
35°, how far above the ground is: the kite? 4 q. 0tt. "S. 'K,' ... 13. A ladder 14 feet long rests against the side ofa building. Thebase of the ladder rests on level ground ... A 24-foot ladder leaning against a building forms an 18° angle with the side of the building.
Answer:
23
Step-by-step explanation:
First subtract 7 and 4.
7-4=3
6-3=3
________
7+3+6+3+4
7+3=10
10+6=16
16+3=19
19+4=23
(Ignore the 3 inside the shape)