Write a polynomial

A farmer packed 3 pints of strawberries every 4 minutes. In the afternoon she packed 2 pints of strawberries every 3 minutes. Wh

MakcuM [25]

Answer:

5 (strawberries / hours)

Step-by-step explanation:

calculation fro morning

strawberries / minutes x minutes / hours = strawberries / hours

so after adding the value in above equation

3/4* 60/1 = 45 strawberries / hours

calculation in the afternoon

strawberries / minutes x minutes / hours = strawberries / hours

2/3 x 60/1 = 40 strawberries / hours

so now by calculating difference between morning and afternoon packing rates, you can easily calculate

45-40 = 5 (strawberries / hours)

8 0

2 years ago

Which of the following is the solution to the following systems of inequalities? (picture included)

Ymorist [56]

Answer:

C. (see the attachment)

Step-by-step explanation:

Both inequalities include the "or equal to" case, so both boundary lines will be solid. That excludes choices A and D.

The first inequality is plotted the same way in all graphs, so we must look at the second inequality. The relationship of y and the comparison symbol is ...

-y ≥ (something)

If we multiply by -1, we get ...

y ≤ (something else)

This means the solution space will be on or below (less than or equal to) the boundary line. This is the shaded area in graph C. (Graph B shows shading above the line.)

___

Further comment

Since the boundary for the second inequality is fairly steep, "above" and "below" the line can be difficult to see. Rather, you can consider the relationship of x to the comparison symbol. For the second inequality, that is ...

x ≥ (something)

indicating the solution space is on or to the right of the boundary line.

3 0

2 years ago

Please help with this question

11111nata11111 [884]

Answer:

QR and CD

Step-by-step explanation:

TQRS is similar to BCDE. Align the letters.

T Q R S

B C D E

Some examples of corresponding sides.

TS and BE

TQ and BC

6 0

2 years ago

Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

7 0

3 years ago

4 2/3 divided by 1/2

ycow [4]

Answer:

9 1/3

Step-by-step explanation:

1. Make 4 2/3 into a improper fraction

4 2/3= 14/3

2. Keep, change, flip

14/3 x 2/1

3. Multiply

14/3 x 2/1= 28/3

4. Simplify

28/3= 9 1/3

(btw keep, change, flip basically means to keep the first fraction the way it is, change the division sign to a multiplication sign, then flip the second fraction so the original denominator is the new numerator, and vise versa.)

3 0

2 years ago

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