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maw [93]
2 years ago
15

Solve this problem 8x + 4(x-1) a. 32x+3 b. 12x-4 c. 12x+4 d. 9x-4

Mathematics
2 answers:
Lilit [14]2 years ago
7 0

Answer:

b

Step-by-step explanation:

8x +4(x -1)

<em>Expand by multiplying 4 into each term inside the bracket:</em>

= 8x +4(x) +4(-1)

= 8x +4x -4

<em>Simplify</em>

= 12x -4

Thus, the answer is b.

riadik2000 [5.3K]2 years ago
4 0

8x + 4(x-1)

Let's start of by applying the distributive property

8x + 4x - 4

Next, let's add the variables.

12x - 4

The answer would be option B.

Hope this helps!

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A bouquet has 6 roses and 21 other types of flowers. What is the ratio of roses to other flowers?
Andrej [43]

Answer:

6:21

Step-by-step explanation:

because there is 6 roses and 21 other types 6/21 = 6:21

7 0
1 year ago
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Let u = &lt;-6, 3&gt;, v = &lt;1, 9&gt;. Find u - v. (5 points)
jeyben [28]

Answer:

u - v = <-7, -6>

Step-by-step explanation:

<-6,3> <1,9>

To get the result you just subtract the components of v from the components of u

<-6 - 1, 3 - 9>

<-7, -6>

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3 years ago
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Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
If you answer this you will get brainless
Yanka [14]

Answer:

B

Step-by-step explanation:

A doesn't repeat at all
B just repeats on the 3
C repeats on the 1 and 3
D repeats on the 5, 1, and 3

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The position of an object moving along a straight line for
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Answer:

at 2/3 seconds

Step-by-step explanation:

S1(t) = t³ + 2

Average speed, dS1/dt = 3t²

S2(t) = t²

Average speed, dS2/dt = 2t

The distance between the objects is

dS1/dt - dS2/dt

= 3t² - 2t

The time the distance between the two object is at minimum is when the distance is 0

That is, when

3t² - 2t = 0

t(3t - 2) = 0

t = 0 or 3t - 2 = 0

t = 0 or t = 2/3

3 0
4 years ago
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