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luda_lava [24]
3 years ago
11

A camp counselor has $53.27 in a bank account and earns an additional $452.68 over summer vacation. The camp counselor spends $1

93.00 on clothes and wants to buy a plane ticket for $298.11.
I NEED HELP ASAP EXPLAIN THINKING
Mathematics
1 answer:
velikii [3]3 years ago
4 0

Answer:

First you do, $53.27+$452.68=$505.95

Next you do, $193+$298.11=$491.11

Last you do, $505.95-$491.11=$14.84

So in the end, the camp counselor will have $14.84 left.

Step-by-step explanation:

Hope that helps! :)

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Answer:

$128.40

Step-by-step explanation:

Find the total cost of the pizza before tax.

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Set up a proportion to find the tax.
7/100 = x/120

Cross multiply

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Divide both sides by 100

Tax = $8.40

$120 + $8.40 = $128.40


I hope this helped and please mark me as brainliest!

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Step-by-step explanation:

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What is 10-c equal to
labwork [276]

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The table represents an exponential function. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4
scoray [572]

Answer:

The multiplicative rate of change of the function is \dfrac{2}{3}

Step-by-step explanation:

You are given the table

\begin{array}{cc}x&y\\ \\1&6\\2&4\\ \\3&\dfrac{8}{3}\\ \\4&\dfrac{16}{9}\end{array}

An exponential function can be written as

y=a\cdot b^x,

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Find a and b. Substitute first two corresponding values of x and y into the function expression:

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Divide the second equality by the first equality:

\dfrac{4}{6}=\dfrac{a\cdot b^2}{a\cdot b^1}\Rightarrow b=\dfrac{2}{3}

Substitute it into the first equality:

6=a\cdot \dfrac{2}{3}\Rightarrow a=\dfrac{6\cdot 3}{2}=9

So, the function expression is

y=9\cdot \left(\dfrac{2}{3}\right)^x

Check whether remaining two values of x and y suit this expression:

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So, the multiplicative rate of change of the function is \dfrac{2}{3}

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MArishka [77]

Answer:

(4)The lowest common denominator of 3 and 8 is 24.

(5) The lowest common denominator of 5 and 10 is 10.

(6) The lowest common denominator of 7 and 3 is 21.

(7) The lowest common denominator of 4 and 5 is 20.

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