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likoan [24]
2 years ago
9

Evaluate (6 +2i) / (3-i).

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
4 0

Answer:

(6 +2i) / (3-i) = (6+2i)/(3-i) x (3+i)/(3+i) = (6+2i)(3+i) / (3-i)(3+i) = 6(3+i)+2i(3+i) / (3)^2-(i)^2 = 18+6i+6i+2i^2 / 9-i^2 = 18+12i+2i^2 / 9-i^2 = 6+12i+2i^2 / 3-i^2 = 2+12i+2i^2 / 1-i^2 = 2+12i+2 / 1 = 4+12ianswer.

qwelly [4]2 years ago
3 0

Answer:

2(4 + 3i) / 5

Step-by-step explanation:

(6 + 2i) (3 + i) / (3 - i) (3 + i)

=> 18 + 12i + 2i² / 9 - i²

=> 16 + 12i / 10

=> 8 + 6i / 5

=> 2(4 + 3i) / 5

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Akimi4 [234]
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Please help!
Reika [66]

Answer:

(1,-5)

Step-by-step explanation:

The given system of inequalities are;

y\:

and

y\:

The point that is a solution will satisfy the two inequalities.

Checking for (1,-5)

-5\: and -5\:

-5\:: True -5\: : True

This point lies in the solution region.

Checking for (1,5)

5\: and 5\:

5\:: False 5\: : False

This point does not lie in the solution region.

Checking for (5,1)

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1\:: False 1\: : True

This point does not lie in the solution region.

Checking for (-1,5)

5\: and 5\:

5\:: True 5\: : False

This point does not lie in the solution region.

4 0
3 years ago
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Can someone please help! i have no clue what im doing
gulaghasi [49]

g(x) = -3x - 8


g(x) = 10

⇒ -3x - 8 = 10

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g(-6) = 10 <==== answer is -6

7 0
3 years ago
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6 0
3 years ago
Please solve the following quadratic equation and show your work: x^2 -x =30
saveliy_v [14]
Rewriting the equation as a quadratic equation equal to zero:
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We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
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Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
     x + 5 = 0  => x = -5
     x - 6 = 0  => x = 6
Therefore, our solutions are x = -5 and x = 6.
8 0
3 years ago
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