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2 years ago

Evaluate (6 +2i) / (3-i).

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

4 0

Answer:

(6 +2i) / (3-i) = (6+2i)/(3-i) x (3+i)/(3+i) = (6+2i)(3+i) / (3-i)(3+i) = 6(3+i)+2i(3+i) / (3)^2-(i)^2 = 18+6i+6i+2i^2 / 9-i^2 = 18+12i+2i^2 / 9-i^2 = 6+12i+2i^2 / 3-i^2 = 2+12i+2i^2 / 1-i^2 = 2+12i+2 / 1 = 4+12ianswer.

qwelly [4]2 years ago

3 0

Answer:

2(4 + 3i) / 5

Step-by-step explanation:

(6 + 2i) (3 + i) / (3 - i) (3 + i)

=> 18 + 12i + 2i² / 9 - i²

=> 16 + 12i / 10

=> 8 + 6i / 5

=> 2(4 + 3i) / 5

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2 years ago

30 points please..I will report your answer if not right Thanks

ella [17]

<h3>Answer: SAS</h3>

=================================

How to get this answer:

We're told that AD = BC, so that is one pair of sides that are congruent. This forms the first "S" in "SAS"

The "A" refers to the congruent angles, which happen to be angle DAB and angle CBA, both are 90 degrees

The second "S" in "SAS" is the second pair of congruent sides. Those two sides are the overlapping shared side of AB. It might help to peel the two triangles apart to get a better look.

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fredd [130]

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Step-by-step explanation:

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