The solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
<h3>How to determine the solution set of the equation?</h3>
The equation is given as:
x^2 + 2x - 48 = 0
A quadratic equation is represented as:
ax^2 + bx + c = 0
By comparing both equations, we have
a = 1, b = 2 and c = -48
The solution of the quadratic equation is then calculated using
x = (-b ± √(b^2 - 4ac))/2a
Substitute values for a, b and c in the above equation
x = (-2 ± √(2^2 - 4 * 1 * -48))/2 * 1
This gives
x = (-2 ± √196)/2
Evaluate the square root of 196
x = (-2 ± 14)/2
Divide through by 2
x = -1 ± 7
Hence, the solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
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The answer is 50 minutes.
Explanation: 10*50=500, 1000-500=500
6*50=300, 800-300=500
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.
The inequality that best represents his practice time is <span>x + y ≥ 45.</span>
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There is way, you just have to divide 1 1/3 by 4 and you get 1/3 ;bs per bag so all the trail mix is distributed equally
Answer:
158cm
Step-by-step explanation:
Data obtained from the question. This includes:
Height of first snow ball (H1) = 7/10m
Height of 2nd snow ball (H2) = 1/2m
Height of 3rd snow ball (H3) = 38cm
Total height of snow man (HT) =?
Next we shall covert from m to cm.
This is illustrated below:
For the first snow ball
1m = 100cm
7/10m = 7/10 x 100 = 70cm
For the 2nd snow ball:
1m = 100cm
1/2m = 1/2 x 100 = 50cm
Now we can obtain the height of the snow man as follow:
Height of first snow ball (H1) = 70cm
Height of 2nd snow ball (H2) = 50cm
Height of 3rd snow ball (H3) = 38cm
Total height of snow man (HT) =?
HT = H1 + H2 + H3
HT = 70 + 50 + 38
HT = 158cm
Therefore the height of the snow man in cm is 158cm
