2 years ago

Evaluate (6 +2i) / (3-i).

2 answers:

4 0

Answer:

(6 +2i) / (3-i) = (6+2i)/(3-i) x (3+i)/(3+i) = (6+2i)(3+i) / (3-i)(3+i) = 6(3+i)+2i(3+i) / (3)^2-(i)^2 = 18+6i+6i+2i^2 / 9-i^2 = 18+12i+2i^2 / 9-i^2 = 6+12i+2i^2 / 3-i^2 = 2+12i+2i^2 / 1-i^2 = 2+12i+2 / 1 = 4+12ianswer.

qwelly [4]2 years ago

3 0

Answer:

2(4 + 3i) / 5

Step-by-step explanation:

(6 + 2i) (3 + i) / (3 - i) (3 + i)

=> 18 + 12i + 2i² / 9 - i²

=> 16 + 12i / 10

=> 8 + 6i / 5

=> 2(4 + 3i) / 5

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Can anyone help me understand how to evaluate the limit of this complex fraction?

SSSSS [86.1K]

Answer:

-1/9

Step-by-step explanation:

$\lim_{x \to 3} \frac{1/x-1/3}{x-3}$

For simplicity, let's multiply top and bottom by 3x:

$\lim_{x \to 3} \frac{3-x}{3x(x-3)}$

Factor out a -1:

$\lim_{x \to 3} \frac{-(x-3)}{3x(x-3)}$

Divide top and bottom by x−3:

$\lim_{x \to 3} \frac{-1}{3x}$

Evaluate the limit:

$\frac{-1}{3(3)}\\-\frac{1}{9}$

It's important to note that the function doesn't exist at x = 3. As x approaches 3, the function approaches -1/9.

5 0

3 years ago

Please help me solve 3x+1/2=3/8+x

gavmur [86]

Answer:

x= - $\frac{1}{32}$

Step-by-step explanation:

First move the x on the right side the the left side. Now your equation is

2x+ $\frac{1}{2}$ = $\frac{3}{8}$ Next move 1/2 to the right side. Now your equation is 4x= $\frac{-1}{8}$ . Next divide both sides by 4 to isolate "x." Now your equation is x= - $\frac{1}{32}$