Answer:
18√2
Step-by-step explanation:
The smaller triangle sharing a vertex with the larger one is similar and half the area. That means its linear dimensions are √(1/2) = (√2)/2 times those of the larger triangle.
The line segment of interest has length ...
36 × (√2)/2 = 18√2
_____
The ratio of area of similar figures is the square of the ratio of their linear dimensions. Thus the ratio of linear dimensions is the square root of the ratio of area.
Answer:
Area=190.091 cm^2
Step-by-step explanation:
Area = 1/2(Pi x r^2) one-half because it's a semi-circle
Area=1/2(3.14 x 11^2)
11^2=121 so, Area=1/2(3.14 x 121)
Area=1/2(379.94)
Area=189.97 cm^2
adjustment:
Area=1/2(3.142 x 11^2)
Area=1/2(3.142 x 121)
Area=1/2(380.182)
Area=190.091
9514 1404 393
Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
__
<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
