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3 years ago

Consider the line y=2/3x

Mathematics

2 answers:

andrew11 [14]3 years ago

7 0

The parallel would be 2/3 and the perpendicular would be 3/2

Lapatulllka [165]3 years ago

3 0

The slope of a line parallel to another has the same slope: 2/3

The slope of a perpendicular line would be the opposite reciprocal: 3/2

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The perimeter of a triangle is 42 yards. The first side is 5 yards shorter than the

nata0808 [166]

Answer: Is your question "What is the length of each side?"

Let x = the length of the second side

Let x - 5 = the length of the first side

Let (x - 5) - 2 = the length of the third side

P = a + b + c

x + x - 5 + x - 7 = 42

3x - 12 = 42

3x = 54

x = 18 yards

x - 5 = 13 yards

x - 7 = 11 yards

Step-by-step explanation:

7 0

2 years ago

Chris is trying to find the volume of a pool. What unit will he use?

jeyben [28]

I'm pretty sure that it's cubic feet not really sure tho sorry

3 0

3 years ago

Read 2 more answers

Dante sold 413 cups of lemonade last weekend. George sold 297 cups of lemonade last weekend. How many more cups of lemonade did

TEA [102]

Answer:dante sold 116 more cups.

Step-by-step explanation: subtract 297 from 413

6 0

4 years ago

Can someone help me out? :P (serious answers only.)

postnew [5]

Answer:

The answer is C 841.62.

I actually got 842.11, but C is the closest answer so that's gonna be the one.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s

Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, $s^{2}$ = sample variance = $97^{2}$ = 9409

n = sample of boxes = 15

$\sigma^{2}$ = population variance

Here for constructing 95% confidence interval we have used chi-square test statistics.

So, 95% confidence interval for the population variance, $\sigma^{2}$ is ;

P(5.629 < $\chi^{2}__1_4$ < 26.12) = 0.95 {As the critical value of chi-square at 14

degree of freedom are 5.629 & 26.12}

P(5.629 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 26.12) = 0.95

P( $\frac{5.629 }{(n-1)s^{2} }$ < $\frac{1}{\sigma^{2} }$ < $\frac{26.12 }{(n-1)s^{2} }$ ) = 0.95

P( $\frac{(n-1)s^{2} }{26.12 }$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{5.629 }$ ) = 0.95

95% confidence interval for $\sigma^{2}$ = [ $\frac{(n-1)s^{2} }{26.12 }$ , $\frac{(n-1)s^{2} }{5.629 }$ ]

= [ $\frac{14 \times 9409 }{26.12 }$ , $\frac{14 \times 9409 }{5.629 }$ ]

= [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0

3 years ago