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3 years ago

2(y-4)+5=3(y+2) for y

Mathematics

2 answers:

MariettaO [177]3 years ago

7 0

Answer:

y = -9

Step-by-step explanation:

<u><em>Expand:</em></u>

2y − 8 + 5 = 3y + 6

<u><em>Simplify 2y-8+5 to 2y-3:</em></u>

2y − 3 = 3y + 6<u><em> </em></u>

<u><em>Subtract 2y from both sides:</em></u>

−3 = 3y + 6 − 2y

<em><u>Simplify 3y + 6 - 2y to y + 6:</u></em>

−3 = y + 6

<em><u>Subtract 6 from both sides:</u></em>

−3 − 6 = y

<em><u>Simplify -3 - 6 to -9:</u></em>

<u>y = −9</u>

brilliants [131]3 years ago

3 0

2(y-4)+5=3(y+2)

multiply the first bracket by 2

(2)(y)=2y

(2)(-4)=-8

multiply the second bracket by 3

(3)(y)=3y

(3)(2)=6

2y-8+5=3y+6

2y-3=3y+6

move 3y to the other side

sign changes from +3y to -3y

2y-3y-3=3y-3y+6

-y-3=6

move -3 to the other side

-y-3+3=6+3

-y=9

multiply both sides by -1 to get +y

(-1)(-y)=9(-1)

Answer:

y=-9

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3 years ago

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koban [17]

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3 years ago

HELP ME!! im so stumped. will give brainliest!

Olegator [25]

Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

4 0

3 years ago

2(y-4)+5=3(y+2) for y​

2(y-4)+5=3(y+2) for y