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Natalka [10]
2 years ago
6

Help me with this please!!!!

Mathematics
1 answer:
Vesna [10]2 years ago
3 0

the first one is C

the second one is D

the third one is B

and the last one is A

All you want to do is count up the y-intercept when it crosses and that gives you the last number (b).

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Write three fractions equivalent to -4/4
Aleonysh [2.5K]

-2/2, -3/3, -1/1

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Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f
AlladinOne [14]

Answer:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

\hat p=0.64 estimated proportion of interest

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:  

Null hypothesis:p =0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

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Step-by-step explanation:

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What is the solution to the equation 93x ≈ 7?
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X= 7/93 or roughly 0.07526... 
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3 years ago
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