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2 years ago

Help me with this please!!!!

Mathematics

1 answer:

Vesna [10]2 years ago

3 0

the first one is C

the second one is D

the third one is B

and the last one is A

All you want to do is count up the y-intercept when it crosses and that gives you the last number (b).

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Tom and Jerry enter a race. Tom runs an average of 10 kilometers per hour, and Jerry runs an average of 9 kilometers per hour. I

Zielflug [23.3K]

I am almost positive that the answer is 45 km

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3 years ago

Read 2 more answers

2x+3y=15 x+y=6 find values for x and y

MatroZZZ [7]

Answer:

(x, y) = (3, 3)

Step-by-step explanation:

Subtract double the second equation from the first.

(2x +3y) -2(x +y) = (15) -2(6)

y = 3 . . . . . . . . simplify

Use the second equation to find x.

x = 6 -y = 6 -3 = 3

The values of x and y are both 3.

8 0

2 years ago

Please help don’t understand

pshichka [43]

Answer:You are going to put and X by the rhombus, the paralleogram, and the trapezoid. All of these shapes have 4 sides.

Step-by-step explanation:

3 0

2 years ago

3 friends share the cost of a gift. The gift costs $70, but the store manager takes $10 off the market price. What amount should

My name is Ann [436]

Answer:

Amount each friend pays for the gift = $20

Step-by-step explanation:

Market price of a gift = $70

The store manager takes $10 off the market price.

Marked down amount = $10

New cost price = Marked price - Marked down amount $=\$70-\$10=\$60$

The cost of the gift is divided among three friends.

This means that the cost of gift which is $60 is divided by three to get each one's contribution in the gift.

∴ Amount each friend pays for the gift $=\frac{60}{3}=\$20$

4 0

2 years ago

Sasha performs an experiment. She chooses one marble from each of three sacks. The first sack has black (B) and white (W) marble

Paladinen [302]

Answer:

Option D is correct

Step-by-step explanation:

From the question, we have:

$Sack\ 1: B, W$

$Sack\ 2: G, Y$

$Sack\ 3: S, R$

Required

The tree diagram

The selection process is as follows:

$Sack\ 1: B, W$

$Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y)$ -- i.e. we write sack 2 as a subset of 1

$Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R))$ -- i.e. we write sack 3 as a subset of 2

<em>The only tree diagram that illustrates this is: option D</em>

5 0

2 years ago