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2 years ago

12

a quarterback threw the football 300 yards over 2 1/2 games.how Manny yards did the quarterback average per game?

1 answer:

Blababa [14]2 years ago

6 0

He averages 120 yards a game

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Simplify x+2/x^2+2x-3 divide by x+2/x^2-x

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

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2 years ago

How much did Mario spend on golfing? a. $35.20 b. $45.20 c. $47.88 d. $143.96

Salsk061 [2.6K]

$47.88 your answer and I am the most important person in the world.

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2 years ago

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Mary's weight went from 80kg to 68kg. express her weight loss as a % of her original weight

Ratling [72]

80-68=12

12/80=0.12

12% is the answer

6 0

2 years ago

Find angle A and angle B..

ExtremeBDS [4]

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

$\tt{\angle{c}=110°}$

and,

$\tt{BC=AC}$

⠀⠀⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

☆Find the $\angle{B} ~and~\angle{A}$

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

Here,

BC =AC

so,

⠀⠀⠀

$\angle{A}=\angle{B}$

we know that,

$\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}$

But $\angle{C}=110°$ (Ģìvéñ)

so..

$\angle{A}+\angle{B}+110°=180°$

$\angle{A}+\angle{A}+110°=180°$

$\because{\angle{A}=\angle{B} }$

$2\angle{A}=180°-110°$

$2\angle{A}=70°$

$\angle{A}=\dfrac{70°}{2}$

$\boxed{\orange{\angle{A}=35°}}$

But...

$\angle{A}=\angle{B}$

soo,

$\boxed{\orange{\angle{B}=35°}}$

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

⠀⠀⠀⠀

$\boxed{\green{\angle{A}=35°}}$

$\boxed{\green{\angle{B}=35°}}$

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2 years ago

Find the values of x and y

IrinaVladis [17]

The value of y=29
the value of x=61

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3 years ago

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