Multiply 64 and 12 three times and 64 ×12=? then ?×3=?
F(x) = x(x -1)
f(3) = 3*2 = 6
f(6) = 6*5 = 30
so f(f(3)) = 30 . . . . . selection A
Answer:
√-1
Step-by-step explanation:
The imaginary number i is defined as √(-1)
NOTE : i² = -1
Answer:
<h2>2/3</h2>
Step-by-step explanation:
This problem bothers on probability
Given that two dice are expected to give an outcome of sum greater than 8
But in the problem statement the first die is already settled since it is showing 6 already.
Now for the second die, the possible outcomes that will add up with the first die to produce a figure greater than 8 are (3,4,5,6)
The probability of obtaining either of these numbers is 4/6= 2/3
<em>Having the first die settled, this means that the probability of obtaining a sum of 8 is 2/3</em>
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Answer:
8.5
Step-by-step explanation:
:)
