40 + 2 + 0.5 + 0.06 + 0.004
Answer:
$831,532.24
Step-by-step explanation:
The amount that will be in her account at ordinary annuity is derived using the formula:
Where:
Yearly Deposit,P=$2000
Annual rate,r=8.8%=0.088
Number of Years,n=43 years
![A(43) = \dfrac{2000((1 + 0.088)^{43}-1)}{0.088}\\\dfrac{2000[(1 .088)^{43}-1]}{0.088}\\A(43)=\$831,532.24](https://tex.z-dn.net/?f=A%2843%29%20%3D%20%5Cdfrac%7B2000%28%281%20%2B%200.088%29%5E%7B43%7D-1%29%7D%7B0.088%7D%5C%5C%5Cdfrac%7B2000%5B%281%20.088%29%5E%7B43%7D-1%5D%7D%7B0.088%7D%5C%5CA%2843%29%3D%5C%24831%2C532.24)
At the end of 43 years, she would have <u>$831,532.24</u> in her account.
Answer:
71.63 kilowatts hours
Step-by-step explanation:
We are told in the question:
John's electricity bill costs $20.90 per month plus $1.23 per kilowatt hour.
We are to find, How many kilowatt hours can he use and keep his monthly cost no more than $109.
Step 1
$109 - $20.90
= $88.1
$88.1 is the amount left to spend on killowatts of electricity per hour after removing the normal monthly electricity bill in a month
Step 2
$1.23 = 1kilowatts per hour
$88.1 = y kilowatts per hour
Cross Multiply
= $1.23 × y kilowatts per hour = $88.1 × 1 kilowatts per hour
y kilowatts per hour = $88.1 × 1 kilowatts per hour/ $1.23
= 71.62601626kilowatts hour.
Approximately = 71.63 kilowatts hour
Therefore, John can use 71.63 kilowatts per hour and keep his monthly cost no more than $109
Answer:
lines r and s
Step-by-step explanation:
we know that
<u><em>Alternate interior angles</em></u> are formed when a transversal passes through two lines. The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles.
When the lines are parallel, the alternate interior angles are equal
so
In this problem
If lines r and s are parallel
then
m∠4=m∠5 ----> by alternate interior angles
