If you answer I’ll make you the brainiest

David can type 90 words a minute.<br> How many words can be typed in 9.5 minutes?

artcher [175]

Answer:

855

Step-by-step explanation:

90x9.5=855

4 0

2 years ago

Read 2 more answers

The price of 10 citrons and 7 fragrant wood apples is 55 units. The price of 7 citrons and 10 fragrant wood apples is 64 units.

a_sh-v [17]

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Further explanation:

Let x be the price of one citron and

y be the price of one fragrant

Then according to given statement

10x+7y = 55 Eqn 1

7x+10y = 64 Eqn 2

Multiplying equation 1 by 7

$7(10x+7y) = 7(55)\\70x+49y=385$

This will be equation 3.

Multiplying equation 2 by 10

$10(7x+10y) = 10(64)\\70x+100y=640$

This will be equation 4.

Subtracting equation 3 from equation 4

$70x+100y - (70x+49y) = 640-385\\70x+100y-70y-49y = 255\\51y = 255\\\frac{51x}{51} = \frac{255}{51}\\x = 5\\Putting\ x=5\ in\ equation\ 1\\10(5)+7y = 55\\50+7y = 55\\7y = 55-50\\7y = 5\\\frac{7y}{7} =\frac{5}{7}$

So,

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Keywords: Linear Equations, Solving system of linear equations

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

What are the measurements of the bases and the area of the trapezoid?

Luda [366]

The bases of the trapezoid are 24 m and 9.6 m.

The area of the trapezoid is 141.12 m².

7 0

3 years ago

A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$