Ask question

Ask question

All categories

3 years ago

10

Molly read 75 pages of the latest thriller mystery novel in 45 minutes. What was her unit rate? If she continues to read at this

rate, how long will it take her to read the entire 425-page novel?

1 answer:

ratelena [41]3 years ago

8 0

Unit rate = 75 pages/45 minutes = 1 1/3 pages/minute

Time to read 425 pages = Total number of pages/Unit rate = 425/1 1/3 =255 minutes = 4 hours and 15 minutes.

You might be interested in

Emily purchased lemons for $600. She sold 3/4 of these at a loss of 20% and the remaining at a gain of 20%. How much percent doe

MAVERICK [17]

Answer:

10%

Step-by-step explanation:

Given: CP of lemon is $600.

3/4 of lemon sold at 20% loss

Remaining lemon at 20% gain.

Considering the quantity of lemon remain constant.

Cost price of 3/4 of lemon= $\frac{3}{4} \times 600= \$450$

As given, 3/4 of lemon sold at 20% loss.

∴ Selling price of $\frac{3}{4}\ of\ lemon= 450- \frac{20}{100}\times 450$

Selling price= $450- 90= \$ 360$

Hence, selling price of 3/4 lemon is $360.

Now, the cost price of remaining lemon $(1-\frac{3}{4} )= (\$ 600-\$ 450)$

∴ The cost price of $\frac{1}{4}\ lemon = \$ 150$

As given, remaining $\frac{1}{4} lemon\ sold\ at\ gain\ of\ 20\%$

∴ Selling price of $\frac{1}{4} \ lemon= (150\times \frac{20}{100}+150)$

Selling price of $\frac{1}{4} \ of\ lemon= (30+150)$

Hence, selling price of 1/4 lemon is $180

Loss\profit percent= $\frac{(SP-CP)}{CP} \times 100$

∴ Loss\profit percent= $\frac{60}{600} \times 100= 10\%$

Hence, the loss percentage is 10%

8 0

3 years ago

PLEASE HELP!!!!!<br> will mark brainliest!!!!!

kati45 [8]

Answer:

<em>X</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>f(</em><em>x)</em>

0 -10

3 -4

5 0

6 2

then now polt the following points on

graph

(<em>0</em><em>,</em><em>-</em><em>1</em><em>0</em><em>)</em><em>,</em><em>(</em><em>3</em><em>,</em><em>-</em><em>4</em><em>)</em><em>,</em><em>(</em><em>5</em><em>,</em><em>0</em><em>)</em><em>,</em><em>(</em><em>6</em><em>,</em><em>2</em><em>)</em>

4 0

3 years ago

Read 2 more answers

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

George bought socks for "$"300 and planned to sell them for $6 a pair. write an inequality to find the minimum number of socks h

Anit [1.1K]

The inequality <u>6s - 300 > 210</u> represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

In the question, we are given that George bought socks for $300.

Therefore, George's total cost = $300.

We assume the number of pairs of socks George sells to be s.

The unit price per pair quoted by George = $6

Therefore, George's total sales = $6s.

We know that the profit over a transaction is given as the difference between sales and costs, that is,

The profit = The total sales - the total costs,

or, profit = 6s - 300.

In the question, we are required to make a profit of more than 210.

This can be shown by the inequality,

6s - 300 > 210.

Thus, the inequality <u>6s - 300 > 210</u> represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

Learn more about inequalities at

brainly.com/question/24372553

#SPJ4

5 0

2 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

3 years ago

Read 2 more answers