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Natasha_Volkova [10]
3 years ago
7

5 1/4 divided by 2/5

Mathematics
2 answers:
Mashcka [7]3 years ago
8 0

Answer:

hello : divided by 2/5

Step-by-step explanation:

51/ 4 divided by 2/5 : (51/4)×(5/2) =255/8

MrMuchimi3 years ago
3 0

Answer:

13 1/8

Step-by-step explanation:

We need to change the mixed number 5 1/4 to an improper fraction

5 1/4 = (4*5+1)/4 = 21/4

5 1/4 ÷ 2/5

21/4 ÷ 2/5

Copy dot flip

21/4 * 5/2

105 / 8

We need to change this back to a mixed number

8 goes into 105  13 times  (13*8 =104)  with 1 left over

13 1/8

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IQ scores based on the​ Stanford-Binet IQ test are normally distributed with a mean of 100 and standard deviation 15. If you wer
lianna [129]

Answer:

95 intervals

Step-by-step explanation:

Given that

population mean = 100

standard deviation = 15

number of interval that involve the mean for 95% confidence interval is calculated as

We know that when we measure the 99 percent confidence interval, 99 outof 100 confidence interval are required to provide the mean population.

similarly

Assuming we measure a confidence interval of 95 percent, then we  should expect 95 out of 100 confidence interval to provide the mean population therefore, answer is 95

7 0
3 years ago
Hi! I was wondering if you could help with this question please :)​
Makovka662 [10]

Answer:

R=\frac{QJ}{I^2t}

Step-by-step explanation:

So we have the equation:

Q=\frac{I^2Rt}{J}

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

(J)Q=(J)\frac{I^2Rt}{J}

Simplify the right:

JQ=I^2Rt

We can rewrite our equation as:

JQ=R(I^2t)

So, to isolate the R variable, divide both sides by I²t:

\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}

The right side cancels, so:

R=\frac{QJ}{I^2t}

And we are done!

7 0
3 years ago
What is the equation of a line which includes points (-5, 5) and (2, 5)?
sveta [45]
<h2>Hello!</h2>

The answer is:

The equation of the line which includes the points (-5,5) and (2,5) is:

y=5

<h2>Why?</h2>

To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)

So, using the points (-5,5) and (2,5), we have:

y-5=\frac{5-5}{2-(-5)}*(x-(-5))

y-5=\frac{0}{2+5}*(x-(-5))

y-5=0*(x+5)

y-5=0

y=5

We have that the equation of the line which includes the points (-5,5) and (2,5) is:

y=5

Have a nice day!

Note: I have attached a picture for better understanding.

8 0
3 years ago
Help I don’t know what I’m doing
Jlenok [28]

Your slope is 6/4. I found this by locating two points where the line intercepts evenly at two points. One was on the y-axis(0,-3) and the other was at (5,3). I then calculated the slope- rise over run or y over x. Because this graphs in a straight line, it is a linear equation. Your equation formula is y = mx + b. M is your slope, and b is your y-intercept. y = 6/4x -3

7 0
3 years ago
What is the answer to 3x+2=3x+2
dalvyx [7]
Do you have answer choices for this question?
8 0
4 years ago
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