Q' (3,2) is the image of Q (6,4) under a translation Use non negative numbers for translation

Mathematics

1 answer:

Leto [7]3 years ago

4 0

Answer:

Q was translated 3 units to the left and 2 units down to get Q'

Step-by-step explanation:

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Solve 5x -c = k for x

inysia [295]

x = $\frac{k+c}{5}$

isolate 5x by adding c to both sides of the equation

5x = k + c ( divide both sides by 5 )

x = $\frac{k+c}{5}$

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3 years ago

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Which rule describes the relationship between the input and output pairs in the following table?

laila [671]

Answer:

Subtract 5 from input.

Step-by-step explanation:

10-5=5

8-5=3

6-5=1

Note:if you need to ask question let me know about it.

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3 years ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = sqrt(25x) and y = x^2/25. Find V b

Westkost [7]

Explanation:

Let $f(x) = \sqrt{25x}$ and $g(x) = \frac{x^2}{25}$ . The differential volume dV of the cylindrical shells is given by

$dV = 2\pi x[f(x) - g(x)]dx$

Integrating this expression, we get

$\displaystyle V = 2\pi\int{x[f(x) - g(x)]}dx$

To determine the limits of integration, we equate the two functions to find their solutions and thus the limits:

$\sqrt{25x} = \dfrac{x^2}{25}$

We can clearly see that x = 0 is one of the solutions. For the other solution/limit, let's solve for x by first taking the square of the equation above:

$25x = \dfrac{x^4}{(25)^2} \Rightarrow \dfrac{x^3}{(25)^3} = 1$

$x^3 =(25)^3 \Rightarrow x = \pm25$

Since we are rotating the functions around the y-axis, we are going to use the x = 25 solution as one of the limits. So the expression for the volume of revolution around the y-axis is

$\displaystyle V = 2\pi\int_0^{25}{x\left(\sqrt{25x} - \frac{x^2}{25}\right)}dx$