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bagirrra123 [75]
3 years ago
12

The carbon dioxide gas that was generated during this reaction was collected at 295K and 125 kPa. If 43.2 L of carbon dioxidegas

was collected, how many grams of glucose (molar mass 180.155 g/mol) were used in this reaction?

Chemistry
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

The balanced equation for this reaction is C2H2 + 502 + 4H2O + 3C02. What volume of carbon dioxide is produced when 2.8 L of oxygen are consumed? 25Explanation:

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0.350g of an organic compound gave 100ml of Nitrogen collected at
LenaWriter [7]

The percentage composition of Nitrogen in the compound is 35.71%

<h3>How to determine the mole of nitrogen</h3>
  • Volume (V) = 100 mL = 100 / 1000 = 0.1 L
  • Pressure (P) = 700 mmHg
  • Temperature (T) = 250 K
  • Gas constant (R) = 62.364 torr.L/Kmol
  • Number of mole (n) =?

Using the ideal gas equation, the mole of nitrogen can be obtained as follow

PV = nRT

n = PV / RT

n = (700 × 0.1) / ( 62.364 × 250)

n = 0.00448 mole

<h3>How to determine the mass of nitrogen</h3>
  • Mole of nitrogen = 0.00448 mole
  • Molar mass of nitrogen = 28 g/mol
  • Mass of nitrogen = ?

Mass = mole × molar mass

Mass of nitrogen = 0.00448 × 28

Mass of nitrogen = 0.125 g

<h3>How to determine the percentage of nitrogen</h3>
  • Mass of nitrogen = 0.125 g
  • Mass of compound = 0.35 g
  • Percentage of nitrogen =?

Percentage = (mass of element / mass of compound) × 100

Percentage of nitrogen = (0.125 / 0.35) × 100

Percentage of nitrogen = 35.71%

Learn more about mass composition:

brainly.com/question/11617445

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6 0
2 years ago
Suppose that the saturation magnetization Mmax of the ferromagnetic metal nickel is 4.41 × 105 A/m. Calculate the magnetic momen
Lady bird [3.3K]

Answer : The magnetic moment of a single nickel atom is 4.82\times 10^{-24}Am^2

Explanation :

Formula used :

M_{max}=(\frac{N}{V})\times \mu

where,

M_{max} = saturation magnetization = 4.41\times 10^5A/m

N = Avogadro's number = 6.022\times 10^{23}atoms/mol

V = volume of nickel atom

\mu = magnetic moment

First we have to calculate the volume of nickel atom.

Density=\frac{Mass}{Volume}

8.90g/cm^3=\frac{58.71g/mol}{Volume}

Volume=\frac{58.71g}{8.90g/cm^3}

Volume=6.59cm^3=6.59\times (100)^3m^3

Now we have to calculate the magnetic moment of a single nickel atom.

M_{max}=(\frac{N}{V})\times \mu

4.41\times 10^5=(\frac{(6.022\times 10^{23})}{6.59})\times (100^3)\times \mu

\mu=4.82\times 10^{-24}Am^2

Therefore, the magnetic moment of a single nickel atom is 4.82\times 10^{-24}Am^2

7 0
3 years ago
997.62 mol = 56.367 L<br> =
Galina-37 [17]
14.626 Gallons because yeah dhhsjsjshshsh
4 0
3 years ago
Which quantity is equivalent to the product of the absolute index of refraction of water and the speed of light in water?
givi [52]

The quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

<h3>What is the speed of light?</h3>

Speed of light is the rate of speed though the light travels. To find the speed of light in any medium, the following formula is used.

v=\dfrac{c}{n}

Here, (n) is the index of reaction and (c) is the speed of light in the vacuum. The speed of light in the vacuum is almost equal to the 3.0×10⁸ m/s.

Now the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water has to be find out.

The above formula can be written as,

v=\dfrac{c}{n}\\vn=c\\c=vn

Here, the product of index of refraction and speed of light is equal to the speed of light in vacuum. This will be true for water as well.

Thus, the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

Learn more about the speed of light here;

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3 0
2 years ago
What unit of measurement would be most useful to find the volume of a standard-sized stapler? A. mm B. mm2 C. mm3 D. cm3
pickupchik [31]
A is your answer okkkkkk
3 0
3 years ago
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