Answer:
The molarity is 0.203 M
Explanation:
Using the formula C(oxi) x V(oxi) / [C(red) x V(red)] = N(oxi) / N(red)
Where oxi and red means reducing agent and oxidising agent respectively.
C = Concentration, V = Volume and N = number of moles.
C(oxi) = 0.5 M
V(oxi) = mL
C(red) = ?
V(red) = 30mL
Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI
so N(red) = 1 , N(oxi) = 2
from the equation above,
C(red) = 0.5 x 25 x 1 / (2 x 30)
= 0.203 M.
Answer:
...
Explanation:
The simple unit conversion tool which helps you to convert atoms to moles or moles to atoms units. Unit Conversion – Moles to Atoms. Atom. Mole. Formula: Mole = Atom * 6.0221415E+23 ... not as 1.8051
With the information given most likely in order to find the partial pressure of the gas produced you have to subtract the total air pressure in the collection flask by the atmospheric pressure since you assume that the flask started with atmospheric pressure when it was sealed and then the gas was added as the reaction took place increasing the pressure.
1.44atm-0.95 atm=0.49atm
Answer:
yaeh
Explanation:
a)Ca(OH)
2
+CO
2
⟶CaCO
3
+H
2
O
No. of atoms:Ca−1;O−4;H−2;C−1
b)Zn+AgNO
3
⟶ZnNO
3
+Ag
No. of atoms:Zn−1;Ag−1;N−1;O−3.
Answer:
131 atm
Explanation:
To find the new pressure, you need to use Boyle's Law:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.
P₁ = 3.88 atm P₂ = ? atm
V₁ = 7.74 L V₂ = 0.23 L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values
30.0312 = P₂(0.23 L) <----- Simplify left side
131 = P₂ <----- Divide both sides by 0.23
