1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zalisa [80]
2 years ago
5

A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea

ch of the following, if n and P do not change? A.) 1100 mL. B.)280 L C.) 87.5 mL?​
Chemistry
1 answer:
Diano4ka-milaya [45]2 years ago
4 0

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

You might be interested in
I need help due today!!!!!
Hitman42 [59]

Answer:

A. 5 g/mL

Explanation:

5 0
3 years ago
Read 2 more answers
Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50
devlian [24]

Answer:

Part A is just T2 = 58.3 K

Part B ∆U = 10967.6 x C_{V} You can work out C_{V}

Part C

Part D

Part E

Part F

Explanation:

P = n (RT/V)

V = (nR/P) T

P1V1 = P2V2

P1/T1 = P2/T2

V1/T1 = V2/T2

P = Pressure(atm)

n = Moles

T = Temperature(K)

V = Volume(L)

R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.

bar = 0.986923 atm

N = 14g/mol

N2 Molar Mass 28g

n = 3.5 mol N2

T1 = 350K

P1 = 1.5 bar = 1.4803845 atm

P2 = 0.25 bar = 0.24673075 atm

Heat Capacity at Constant Volume

Q = nCVΔT

Polyatomic gas: CV = 3R

P = n (RT/V)

0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))

V = (nR/P) T

V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K

V = (0.28721/1.4803845) x 350

V = 0.194 x 350

V = 67.9036 L

So V1 = 67.9036 L

P1V1 = P2V2

1.4803845 atm x 67.9036 L = 0.24673075 x V2

100.52343693 = 0.24673075 x V2

V2 = P1V1/P2

V2 = 100.52343693/0.24673075

V2 = 407.4216 L

P1/T1 = P2/T2

1.4803845 atm / 350 K = 0.24673075 atm / T2

0.00422967 = 0.24673075 /T2

T2 = 0.24673075/0.00422967

T2 = 58.3 K

∆U= nC_{V} ∆T

Polyatomic gas: C_{V} = 3R

∆U= nC_{V} ∆T

∆U= 28g x C_{V} x (350K - 58.3K)

∆U = 28C_{V} x 291.7

∆U = 10967.6 x C_{V}

5 0
3 years ago
Methanol and butanol are alcohols. Alcohols have the same_______________ as alkanes and the __________ identifies the compound a
Margarita [4]

Answer:

Methanol and butanol are alcohols. Alcohols have the same_______________ as alkanes and the __________ identifies the compound as an alcohol.

Explanation:

Alcohols belong to a group of organic compounds which contain -OH group as the functional group.

So alcohols have the same carbon -hydrogen bonds as alkanes and the        -OH functional group identifies the compound as an alcohol.

8 0
2 years ago
Which of the following pieces of information is given in a half-reaction?
puteri [66]

Answer:

<em>The number of electrons transferred in the reaction</em>

Explanation:

8 0
3 years ago
UNDERSTANDING CONCEPTS-Fill in the Blanks:
igomit [66]

Answer:

17 decrease

18 increase

19 increase

20 decrease

Explanation:

6 0
3 years ago
Other questions:
  • The product formation was decreased when a substance b was added to an enzyme reaction. more substrate being added did not incre
    13·1 answer
  • According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?
    6·1 answer
  • Marshall determines that a gas has a gage pressure of 276 kPa what's the absolute pressure of this gas
    13·2 answers
  • Suppose an EPA chemist tests a 250.0 ml sample of groundwater known to be contaminated with nickel(II) chloride, which would rea
    8·1 answer
  • What is the primary unit of mass
    6·1 answer
  • Which phrase best defines a prototype? The final product, which has undergone extensive testing and redesign a model that has be
    13·1 answer
  • The number of electrons that can be held in the second orbit
    6·1 answer
  • A 12 fluid ounce Coca-Cola contains 6.9*10^22 molecules of sugar (C12H22O11). How many grams of sugar are there in a coke?
    14·1 answer
  • What would you need to do to calculate the molality of 10 mol of NaCl in 200
    14·1 answer
  • Part 1: Fill in the blank<br> Newton’s Second Law: Unbalanced forces cause an object to ______.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!