<span>39, 41, 33, 57, 34, 30, 47, 33, 49, 52, 32, 53, 37, 43
Step 1: Order the data from least to greatest:
30, 32, 33, 33, 34, 37, 39, | 41, 43, 47, 49, 52, 53, 57
40
Find the median: 40 (use | to mark this on the box plot)
Find the lower and upper extremes: 30 and 57
Find the middles of the lower and upper halves (called lower and upper quartiles) (see bold): 33 and 49; This is where the box is formed.
These are the 5 numbers used to create the box plot.
Choice C uses these number to create the box plot.
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Answer:
total amount of students in the class = 24
the amount of boy students in the class = 8
the amount of girl students in the class = ?
a) we know how many boys are in so B=8/24
b) know you calculate the amount of girl students in the class
totally they are 24 students are found we know the boys then the last are girls to know how many girls are in there
24 - 8 = 16 girls.
G=16/24
Answer:
Step-by-step explanation:
With replacement of the first ball
P(first ball is red and the second is green) =7/19 * 9/19= 63/361=.175
without replacement (14 total balls in the urn on the second draw)
P(first ball is red and the second is green) =7/18 * 9/18= 63/324=.194
Ok so
parabola standard form is
y=ax^2+bx+c
if you have the points
(-2,18)
(0,4)
(4,24)
sub points to find a,b and c
(-2,18)
sub -2 for x and sub 18 for y
18=a(-2)^2+b(-2)+c
18=4a-2b+c
(0,4)
sub 0 for x, nice a, an b cancel
4=a(0)^2+b(0)+c
4=0+0+c
4=c
we can sub that back later
(4,24)
24=a(4)^2+b(4)+c
24=16a+4b+c
we have
18=4a-2b+c
c=4
24=16a+4b+c
sub 4 for c
18=4a-2b+4
24=16a+4b+4
minus 4 from both sides
14=4a-2b
20=16a+4b
simlify all equations
7=2a-b
5=4a+b
add to solve for 6a
12=6a+0b
12=6a
divide both sides by 6
2=a
sub back
7=2a-b
7=2(2)-b
7=4-b
-3=b
equation is
y=2x^2-3x+4
