Question

Hi please answer the question below in the photo, While doing it could you also add your steps to get to your solution in a simple way! Thank you!

Answer 1

Answer:

4

Step-by-step explanation:

$(3^8 \cdot 2^{-5} \cdot 9^0)^{-2} \cdot (\dfrac{2^{-2}}{3^3})^4 \cdot 3^{28} =$

$= 3^{-2 \times 8} \cdot 2^{-5 \times (-2)} \cdot 1 \cdot \dfrac{2^{-2 \times 4}}{3^{3 \times 4}} \cdot 3^{28}$

$= 3^{-16} \cdot 2^{10} \cdot \dfrac{2^{-8}}{3^{12}} \cdot 3^{28}$

$= \dfrac{2^{10} \times 3^{28}}{3^{16} \cdot 2^{8} \cdot 3^{12}}$

$= \dfrac{2^{2} \times 3^{28}}{3^{28}}$

$= 4$

Answer 2

Answer:

4

Step-by-step explanation:

Please find attached my workings (Brainly equation editor is not working for me at the moment)