By definition we have that the average rate of change is given by:
AVR = (f (x2) - f (x1)) / (x2 - x1)
Substituting the values we have:
AVR = (204 - (-6)) / (10 - 0)
Rewriting we have:
AVR = (204 + 6) / (10 - 0)
AVR = 210/10
AVR = 21
Answer:
the average rate of change for f (x) from x = 0 to x = 10 is:
AVR = 21
It allows students to see the importance of their own learning process. Process Recognition: Students can identify what they did well, what they failed at, what they need to change.
<u>c.)44 kilometers</u>
Answer:
Solution given:
let
length =L
and
Area =A
Now
we have
Area [A]=1936 square kilometers
now
As we know that
Area of square :length *length
A=l*l
A=l²
Substituting value of A
1936=l²
doing square root on both side
![\sqrt{1936}=\sqrt{l²}](https://tex.z-dn.net/?f=%5Csqrt%7B1936%7D%3D%5Csqrt%7Bl%C2%B2%7D)
we get
l=![\sqrt{2*2*2*2*11*11}](https://tex.z-dn.net/?f=%5Csqrt%7B2%2A2%2A2%2A2%2A11%2A11%7D)
l=2*2*11
l=44 kilometers
So
<u>the length of one side of a </u><u>square</u><u> </u><u>is</u><u> </u><u>4</u><u>4</u><u> </u><u>kilometers</u><u>.</u><u />