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ivolga24 [154]
3 years ago
13

Graph the linear equation. Find three points that solve the equation, then plot on the graph. -3y=x-6

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

Step-by-step explanation:                               x - 6

The given equation can be re-written as y = ---------                              

                                                                             -3

Arbitrarily choose x = 0.  Then:

      x - 6         0-6

y = --------- = ----------- = 2, so (0, 2) is a point on the graph which is also the                              

          -3            -3                                                                  y-intercept

Arbitrarily choose x = 6.  Then y = 0, and (6, 0) is another point on the graph                                    

                                                              which happens to be the x-intercept

arbitrarily choose x = 12.  Then y = (12 - 6) / (-3) = -2.  Then  (12, -2) is            

                                                                                  another point on the

                                                                                  graph.

Plot (12, -2), (6, 0) and (0, 2).  Draw a line through these three points.

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What are the last three terms of the binomial expansion 32x³ + 80x'y + 80x³y² +
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The last three terms of the given binomial expansion are 40x²y³ + 10xy⁴ + y⁵

<h3>Binomial expansion</h3>

From the question, we are to determine the last three terms of the binomial expansion 32x⁵ + 80x⁴y + 80x³y² + __ + __ + __

The highest power of the expansion is 5

Using the binomial expansion theorem

(m +n)⁵ = m⁵ + 5m⁴n + 10m³n² + 10m²n³ + 5mn⁴ + n⁵

Now, we will determine the values of m and n by comparison

By comparison,

m⁵ = 32x⁵

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∴ m = 2x

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5m⁴n = 80x⁴y

Divide both sides by 5, to get

m⁴n = 16x⁴y

Put m = 2x into the equation

(2x)⁴n = 16x⁴y

16x⁴n = 16x⁴y

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Thus, the expression being expanded is (2x + y)⁵

By binomial expansion, the expansion of (2x + y)⁵  is

(2x + y)⁵ = (2x)⁵ + 5(2x)⁴y + 10(2x)³(y)² + 10(2x)²(y)³ + 5(2x)(y)⁴ + y⁵

(2x + y)⁵ = 32x⁵ + (5×16)x⁴y + (10×8)x³(y)² + (10×4)x²(y)³ + (5×2)x(y)⁴ + y⁵

(2x + y)⁵ = 32x⁵ + 80x⁴y + 80x³y² + 40x²y³ + 10xy⁴ + y⁵

Hence, the last three terms of the given binomial expansion are 40x²y³ + 10xy⁴ + y⁵

Learn more on Binomial expansion here: brainly.com/question/13602562

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