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2 years ago

Angle r° = 2w°. What is the measure of angle r°? 120° 240° 143° 286°

Mathematics

1 answer:

Tanya [424]2 years ago

4 0

Answer:

D = 286°

Step-by-step explanation:

Find both the angles of each right triangle.

Triangle A : 53°, 37°, 90°

180° - 127° = 53°

53° + 90° = 143°

180° - 143° = 37°

Triangle B: 90°, 53°, 37°

180° - 127° = 53°

53° + 90° = 143°

180° - 143° = 37°

Now, we find w.

w = 180° - 37° = 143°

r = 2w = 143 × 2

r = 286°

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2 years ago

Now, look at the set of integers. Complete the table for the closure property if integers under the four operations.

Kisachek [45]

Answer:

See below.

Step-by-step explanation:

Addition: closed

Example: -5 + 10 = 5, and -5, 10, and 5 are all integers

Subtraction: closed

Example: 10 - 8 = 2, and 10, 8, and 2 are all integers

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Example: 5/2 = 2.5, and 2.5 is not an integer, although 2 and 5 are integers

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3 years ago

A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.31 lb, the mean of all of the weight

a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 lb, and the standard deviation of the weights is s=1.968 lb.

This means that $\mu = 2.088, \sigma = 1.968$

a. What is the difference between the weight of 5.31 lb and the mean of the weights?

This is $X - \mu = 5.31 - 2.088 = 3.222$

The difference is of 3.222 lbs.

b. How many standard deviations is that [the difference found in part (a)]?

This is the z-score. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.31 - 2.088}{1.968}$

$Z = 1.64$

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the weight of 5.31 lb significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

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3 years ago