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sertanlavr [38]
3 years ago
7

Which of these shapes have the same area?

Mathematics
1 answer:
zvonat [6]3 years ago
3 0

Answer:

wheres the picture?

Step-by-step explanation:

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Solve using quadratic formula.<br><img src="https://tex.z-dn.net/?f=4%20%7Bs%7D%5E%7B2%7D%20%2B%208s%20%2B%204%20%3D%200" id="Te
lianna [129]
S = - 1
Hope this help!
3 0
3 years ago
Help me pls.
salantis [7]

Answer:

1. 424

2.471

3.512

Step-by-step explanation:

1. 10×12+8×10+8×13+8×15

=120+80+104+120

=424

2. 5×24+9×24+9×15+9×15

=120+216+135

=471

3. 24×16+2×24+2×20+2×20

=384+48+40+40

=512

3 0
3 years ago
Read this scenario and answer the question that follows it.
Aleks [24]
By increasing the number of blue widgets supplied
5 0
3 years ago
Read 2 more answers
A garden measuring 9 meters by 4 meters is going to have a walkway constructed all around the perimeter, increasing the total ar
marysya [2.9K]

Answer:

3 metres

Step-by-step explanation:

Let the width of the pathway be x

Area: (9+2x)(4+2x)

36 + 8x + 18x + 4x²

4x² + 26x + 36

Increased area is 150:

4x² + 26x + 36 = 150

4x² + 26x - 114 = 0

2x² + 13x - 57 = 0

2x² + 19x - 6x - 57 = 0

x(2x + 19) - 3(2x + 19) = 0

(x - 3)(2x + 19) = 0

x = 3, x = -19/2

4 0
3 years ago
Read 2 more answers
Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
2 years ago
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