Answer:
$12
Step-by-step explanation:
If we stuck with the price of $8, then we end with an income of $2400
Increasing it by $1 will decrease attendance by 20
8 x 300 = 2400
9 x 280 = 2520
10 x 260 = 2600
11 x 240 = 2640
12 x 220 = 2640
13 x 200 = 2600
We're starting to go down, so let's stop there
The ticket price of $11 or $12 appears to give the most income
I would stick with $12 since your still getting more money from one ticket
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
<u><em>Either A or D</em></u>
Step-by-step explanation:
<u><em>I got It right Hope it helps this you guys</em></u>