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Salsk061 [2.6K]
4 years ago
11

PLEEEAAAASSSEE HEEEELLLLPP ME BRAINLIEST ANSWER PLUS 10 PTS!!!!!!!!

Mathematics
2 answers:
lesya [120]4 years ago
8 0
A. 35x + 1,500 > 3,250
<span>He has already typed 1500.
He needs to type more than 3250 total.

</span>Hope I helped :)
Anna35 [415]4 years ago
7 0
It would be A

If you rearrange A, you get: 35x > 3250 - 1500
35x > 1750 (meaning, he still has another 1750 words left to type to hit his 3250 target)
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The correct answer is A.6
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What is the equation of a line that has a slope of 2 and passes through the point (-6, 3)?
musickatia [10]

Answer:

y=2x+15

Step-by-step explanation:

Idk if you still need help but this is the answer.

Explanation:

You want to find the equation for a line that passes through the point (-6,3) and has a slope of 2.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 2. So you can right away fill in the equation for a line somewhat to read:

y=2x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-6,3). When x of the line is -6, y of the line must be 3.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-6,3).

So, why not plug in for x the number -6 and for y the number 3? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-6,3). y=mx+b or 3=2 × -6+b, or solving for b: b=3-(2)(-6). b=15.

The equation of the line that passes through the point (-6,3) with a slope of 2

is y=2x+15

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goldfiish [28.3K]

Answer:

\sf 1. \quad \tan(B)=\dfrac{4}{3}

\sf 2. \quad \tan(A)=\dfrac{7}{2}

\sf 3. \quad \angle A

Step-by-step explanation:

<u>Acute angle</u>: an angle less than 90°

<u>Tan trigonometric ratio</u>

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

<u>Question 1</u>

Refer to the first attached diagram.

If tan(A) = 3/4 then the side opposite ∠A is 3 units, and the side adjacent ∠A is 4 units.

Therefore:

\implies \sf \tan(B)=\dfrac{4}{3}

<u>Question 2</u>

Refer to the second attached diagram.

If tan(B) = 2/7 then the side opposite ∠B is ,and the side adjacent ∠B is 7.

Therefore:

\implies \sf \tan(A)=\dfrac{7}{2}

<h3><u>Question 3</u></h3>

Angle A would be bigger (see second attachment).

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Answer:

m√n+2n-n√m

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m√n+2n-n√m

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3 years ago
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