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erica [24]
2 years ago
12

What is the measure of the indicated angle? A 180° B 110° C 70° D 90°

Mathematics
1 answer:
ikadub [295]2 years ago
8 0

Answer:

D. 70°

Step-by-step explanation:

the sum of the unknown angle and 110° is 180 °

so, let the unknown angle be x

x+110 = 180

x = 180-110

x = 70°

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The two-way table shows the number of students that would rather be a member of the band or chorus if they could only choose one
sergey [27]

Answer:

There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.

There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.

Students in Grade 8 are more likely to be members of the band.There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.

There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.

Students in Grade 8 are more likely to be members of the band.

4 0
3 years ago
Please help! It’s late!
zmey [24]

Answer:

b.13 hope this helps. have a good night

4 0
2 years ago
Read 2 more answers
Hello will you help me with this?
Norma-Jean [14]

Answer:

A. 432=18x

B. 22-see explanation

C. 24

D. See if your rounded answer and the actual answer are close.

Step-by-step explanation:

A. He buys a new phone for $432, and pays each month. We will use the variable x, and "x" will represent how many months he pays. It says that he pays $18 per month, so the equation would be 432=18x.

B. We need to isolate x, and to do this we have to divide 432 by 18. To approximate this answer, round 432 to 440 and 18 to 20. Now, divide 440 by 20. We get 22, so this will be the estimation.

C. Divide 432 by 18. We get 24.

E. You can see if it is reasonable if they are close in value.

4 0
3 years ago
The graph below shows the average daily temperature over the period of a year. Explain how each labeled section of the graph rel
klemol [59]
Remark
I'm going to assume you are in the Northern Hemisphere. 

Answer
A looks like you are beginning in Winter. The temperature is down quite a bit. That would be about October where I live. B is spring because the temperature is rising but not at it's peak. That would be about April May here. 

C is summer. Glorious warm summer. June July and August.

D is autumn. The temperature is falling and it is just about at it's low peak again. 
7 0
3 years ago
Read 2 more answers
How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title
kotegsom [21]
Let t=\sqrt y, so that t^2=y, t^4=y^2, and \mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}. Then

\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}

Now let y=\sqrt2\tan z, so that \mathrm dy=\sqrt2\sec^2z\,\mathrm dz. Then

\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C

Transform back to y to get

\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C

and again to get back a result in terms of t.

\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C
3 0
3 years ago
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