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evablogger [386]
2 years ago
6

Please i need your help

Mathematics
1 answer:
Scrat [10]2 years ago
6 0

Answer:

1. YES, BECAUSE WITH TAX, IT WOULD BE 9.88

2. MOVE THE DECIMAL OVER TO THE LEFT BY ONE PLACE

ANSWER IS 5.356

Step-by-step explanation:

IF TAX IS 13% YOU MULTIPLE 8.75 BY 1.13. YOU GET 1.13 FROM THE ORIGINAL PRICE PLUS .13 IN TAX.

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Anna has leaned a ladder against the side of her house. If the ladder forms a 72º angle with the ground and rests against the ho
LuckyWell [14K]

Answer:

(A) 2 meter

Step-by-step explanation:

It is given that the ladder forms a 72º angle with the ground and rests against the house at a spot that is 6 meters high.

Let the measure of bottom of the ladder from the wall be x, then using the trigonometry, we have

\frac{CB}{AB}=tan72^{\circ}

\frac{6}{x}=tan72^{\circ}

\frac{6}{x}=3.077

x=\frac{6}{3.077}

x=1.94

x≈2m

Thus, option A is correct.

6 0
3 years ago
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shutvik [7]
A heptagon has 7 sides.

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Answer: The final angle must be 124°
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What is the correct placement of the value -3
sdas [7]
It is thousandths because it t is 3 plac s the the left
5 0
3 years ago
Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2
Phoenix [80]

Answer:

B

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = \sqrt{3} , then letting the altitude be h

tan60° = \frac{opposite}{adjacent} = \frac{11\sqrt{6} }{h}  = \sqrt{3} ( multiply both sides by h )

11\sqrt{6} = h × \sqrt{3} ( divide both sides by \sqrt{3} )

11\sqrt{2} = h

using the sine ratio in the triangle on the left and the exact value

sin45° = \frac{\sqrt{2} }{2} , then

sin45° = \frac{opposite}{hypotenuse} = \frac{h}{x} = \frac{11\sqrt{2} }{x} = \frac{\sqrt{2} }{2} ( cross- multiply )

\sqrt{2} × x = 22\sqrt{2} ( divide both sides by \sqrt{2} )

x = 22

6 0
1 year ago
James is participating in a 5-mile walk to raise money for a charity. he has received $200 in fixed pledgesand raises $20 extra
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5x20=100 100+200=300 or atlas what i think if this is wrong i am sry but if isn't I'm glad I'm able to help ^u^

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