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Colt1911 [192]
2 years ago
9

Select all expressions that are equivalent to 5n-30

Mathematics
1 answer:
mamaluj [8]2 years ago
8 0

Answer: everything EXCEPT 5(n-30)

Step-by-step explanation:

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Jayden and Jacques went to the park to play. They were gone for an hour and fifteen minutes. They ot home at 12: 30 pm. What tim
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Answer:

11:15

Step-by-step explanation:

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How do you move the decimal point to find 1% of a number
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You won't want to move the decimal if you're finding 1%.
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How do you do these two questions?
nignag [31]

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

5 0
3 years ago
Write the equation of the line parallel to the
kakasveta [241]

Answer:

x=-7

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If a line is parallel to the y-axis, then it is vertical because the y-axis is vertical.

A vertical line is in the form of x=a number.

Since the line we are looking for is 7 units to the left of the y-axis, then the line is x=-7.  -7 is 7 units left of 0.

7 units right would have been x=7.

3 0
3 years ago
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The circumference of a circular mat is 13π feet. What is the area, in square feet, of the mat? Express your answer in terms of π
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\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=13\pi \end{cases}\implies 13\pi =2\pi r\implies \cfrac{13\pi }{2\pi }=r\implies \boxed{\cfrac{13}{2}=r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad \implies A=\pi \left(\cfrac{13}{2} \right)^2\implies A=\pi \left( \cfrac{13^2}{2^2} \right)\implies A=\cfrac{169}{4}\pi

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2 years ago
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