Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54
Answer:
it is b
Step-by-step explanation:
G(f(4)) = g(4-7) = g(-3) = (-3)² = 9
g(f(4)) = 9
The next step of your proof is to subtract (a/b) from both sides.
Then you get, x = (m/n) - (a/b)
Since rationals are closed over addition, (m/n) + (-a/b) is a rational number.
Therefore, x (an irrational number) = a rational number <em>This is a false statement which is a contradiction. So, the assumption was incorrect.</em>
Thus, the sum of a rational and irrational number is an irrational number. QED