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3 years ago

Help help help (11 points)

Mathematics

1 answer:

Papessa [141]3 years ago

5 0

Answer:the answer should be 12

Step-by-step explanation:when having a 1 as the exponent that means that you multiply that number one time so 2 times 2 equals 4 and then 3 times 4 equals 12.hope it helps.

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strojnjashka [21]

51*39*28=55692
55692*95/100=52907.4
52907+3455.75= 56363.15
55692-56363.15=-671.15

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8 0

3 years ago

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12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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3 years ago

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Fofino [41]

Um 20% at least i think

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4 years ago

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il63 [147K]

Answer:

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What is the GCF of h4 and h8

Naily [24]

The greatest common factor is to h4 and h8 is 4

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3 years ago