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marissa [1.9K]
2 years ago
10

HELP MEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
lana66690 [7]2 years ago
7 0
The answer is D. y=-1/2x
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What is the circumference and the area of this circle​
alexira [117]
<h2>circumference = 50.24cm</h2><h2>area = 200.96cm²</h2>

Step-by-step explanation:

radius (r) = 8cm

circumference = 2π×r

= 2 × 3.14 × 8

= 50.24cm

area = π × r²

= 3.14 × 8 × 8

= 200.96cm²

<h2>MARK ME BRAINLIST</h2>
3 0
3 years ago
The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer th
castortr0y [4]
  <span>s = 60t - 3t^2 
v = ds/dt = 60 - 6t 

when it comes to rest, v = 0, 
so t = 10 sec 

now distance travelled = time taken x average velocity 
= 10 x (60 + 0)/2 
= 300 ft 

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6 0
3 years ago
ellen had 25 hair clips,7 of them were blue and the rest are purple.what percent of hair clips were purple
strojnjashka [21]
Answer=72%

25-7=18purple clips

  18       x
____=____
  25     100

cross multiply
25x=1800
divide both sides by 25
x=72%
6 0
3 years ago
Read 2 more answers
In abc above,what is the length of ad​
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = \frac{\sqrt{3} }{2}, thus

sin60° = \frac{opposite}{hypotenuse} = \frac{BD}{BC} = \frac{BD}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

2BD = 12\sqrt{3} ( divide both sides by 2 )

BD = 6\sqrt{3}

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = \frac{1}{\sqrt{3} } , thus

tan30° = \frac{opposite}{adjacent} = \frac{AD}{BD} = \frac{AD}{6\sqrt{3} } = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} AD = 6\sqrt{3} ( divide both sides by \sqrt{3} )

AD = 6 → B

4 0
3 years ago
Rewrite the following as single exponent using product rule:<br><br> 9^6 x 9^1
marissa [1.9K]
To rewrite it as a single exponent we have to simply add the exponents since we have an equal base.
The answer is 9^7

3 0
2 years ago
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