(3x^2+9x-6) - (2x^3-4x^2+6x-4)
Short Answer
2x^3+7x^2+3x-2
Step by Step
1.)2x^3 doesn’t subtract from anything because there are no other trinomials
2.)3x^2 - (-)4x^2 = 7x^2 because a double negative cancels out and you end up adding them
3.)9x-6x=3x
4.)-6 - (-)4 = -2 because double negatives cancel out into addition
Answer:
Step-by-step explanation:
1. multiply both sides by 2
<em>3b-4=2c</em>
2. add 4 to both sides
3b=2c+4
3. divide both sides by 3
b= 
Answer:
A
Step-by-step explanation:
First, put this equation in slope intercept form.

Where m is the slope and b is the y intercept.

Since it's greater than, the solution set is above the line, effectively eliminating graph D.
Now we should graph it.
We can see that the point
is on the graph, and only Graph A has that point. Therefore, Graph A is the correct graph.
<span>Twice the sum of a number and 3 = 2(n + 3)
</span><span>three times the difference of the number and 3 = 3(n - 3)
so
</span><span>Twice the sum of a number and 3 is equal to three times the difference of the number and 3:
</span>2(n + 3) = 3(n - 3)
2n + 6 = 3n - 9
n = 15
answer
2(n + 3) = 3(n - 3)
n = 15
You can do 8 + 8 = 16 then minus 1 cuz thats how much you added