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2 years ago

How to evaluate 3(2x-4)-6x+12

Mathematics

1 answer:

Inessa [10]2 years ago

7 0

Answer:

Step-by-step explanation:

6x-12-6x+12=

0x-12+12=0

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Write fractions I order from least to greatest.

alekssr [168]

2/5 is equal to 0.4
1/3 is equal to 0.33
5/6 is equal to 0.83
4/8 is equal to 0.5
5/12 is equal to 0.42
1/6 is equal to 0.17
7/100 is equal to 0.07
9/10 is equal to 0.9
4/5 is equal to 0.8

so from least to greatest: 7/100, 1/6, 1/3, 2/5, 5/12, 4/8, 4/5, 5/6, 9/10
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3 0

3 years ago

g Suppose I will flip a fair coin until it lands Heads for the first time, and you will receive $2 if the game lasts for 1 round

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

The main idea is that I would like to pay less than what I'm expecting to win, so in that way, I get a profit out of playing this game. Let X be the number of tosses until I get a Heads. By definition, this is a geometric random variable with parameter p = 1/2.

Let Y the amount I received for playing. So, we want to calculate the expected value of Y.

We can calculate it as follows

$E[Y] = 2 P(X=1)+ 4 P(X=2)+ 8 P(X =3) + \dots = \sum_{n=1}^infty 2^n P(X=n)$

Since X is a geometric random variable, we have that $P(X=n) = (\frac{1}{2})^{n-1}\frac{1}{2}$

Then,

$E[Y] = \sum_{n=1}^\infty 2^{n} (\frac{1}{2})^{n-1} \frac{1}{2} = \sum_{n=1}^\infty 2^{n-1} \cdot \frac{1}{2^{n-1}} = \sum_{n=1}^\infty 1 = \infty$

So, we expect to have an infinite amount. Given this, we can pay as much as we want to play the game.

5 0

3 years ago

Heather is going to graph y= -3x^2 +3. How is the parent graph transformed

Akimi4 [234]

Well compared to the parent function x^2, the graph of y=-3x^2+3 is flipped upside down (negative sign), steeper, and is up 3 units from the origin.

6 0

4 years ago

Factor the expression below.

dexar [7]

Answer:

A,(x-6)(x-6)

or simply

${x - 6}^{2}$

5 0

4 years ago

Let the function f be defined by the equation

Archy [21]

Answer:

Domain: $(-\infty,\infty)$

Step-by-step explanation:

The domain of a function is all values of x such that f(x) exists.

In our case we have the following function:

$f(x)=x^{3}-5x+3$

We know that x and f(x) are real numbers, therefore the domain will be the interval $(-\infty,\infty)$ , or in other words, the domain is all real numbers.

I hope it helps you!

5 0

3 years ago