Answer:
375,000,000 milliliters of water is in the pool.
Step-by-step explanation:
We know
1 liters = 1000 milliliters
hence to convert liter in to milliliter we have to multiply the liter unit with 1000 to get the milliliter
we have to find value of 375,000 liters in milliliters
to get that we multiply both side by 375,000
1* 375,000 liters = 1000* 375,000 milliliters
thus,
375,000 liters = 375,000,000 milliliters
thus, there is 375,000,000 milliliters of water is in the pool.
Answer:
V=2,685,410.22
Step-by-step explanation:
with rectangles, to find volume you use this formula: V=L times W times H
volume equals length times width times height
<em>Now with this info lets use the formula:</em>
<u>Length times width:</u>
30.3 times 20.75=628.75 or base.
<em>Sometimes people use base times height, base is length times width</em>
<u>Base times height:</u>
628.75 times 4,271.2= 2,685,410.22
I really hope this helps u!
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Answer:
I believe it is 10110
Step-by-step explanation:
hope this helps
Like terms are terms that have the same variable no matter the coefficient value such as a negative or positive coefficient (number right to left of the variable aka the letter representing an unknown amount of value).
A. 8n : - 4n becuase the have the same variable (N)
B. - 2d: D because they have the same variable and even if d has no coefficient, it still has value, variables with no coefficient always equal 1 no matter the circumstances
C. - b: 17b and -3b2 because they both have the same variable eliminating the coefficients being two different types of numbers (positive and negative). The expressions have to have the same variable.
D: 4y², -3y2,4y, and 4 to the second power. This is because they all have the same variable.
E. 6x2y: 3xy because the variable are specifially xy and they must be in order to be like terms.
abc: all because they have all the letters but are just in different orders of variables. (thats all)
Here's the general formula for bacteria growth/decay problems
Af = Ai (e^kt)
where:
Af = Final amount
Ai = Initial amount
k = growth rate constant
<span>t = time
But there's another formula for a doubling problem.
</span>kt = ln(2)
So, Colby (1)
k1A = ln(2) / t
k1A = ln(2) / 2 = 0.34657 per hour.
So, Jaquan (2)
k2A = ln(2) / t
<span>k2A = ln(2) /3 = 0.23105 per hour.
</span>
We need to use the rate of Colby and Jaquan in order to get the final amount in 1 day or 24 hours.
Af1 = 50(e^0.34657(24))
Af1 = 204,800
Af2 = 204,800 = Ai2(e^0.23105(24))
<span>Af2 = 800</span>