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solmaris [256]
2 years ago
14

Page

Mathematics
1 answer:
ioda2 years ago
4 0

Step-by-step explanation:

I just answered this. so here again :

let's start with

1 inch = 2.54 cm

1 ft = 12 in = 2.54×12 = 30.48 cm

1 yd = 3 ft = 3×30.48 = 91.44 cm

1 meter = 100 cm

this should be enough to answer the problems :

a.)

25 ft = 25 × 30.48 cm = 762 cm = 762/100 m = 7.62 m

b.)

67 m = 6700 cm = 6700/2.54 in = 2,637.795276... in

c.)

8.5 yd = 8.5 × 91.44 cm = 777.24 cm

d.)

90 cm = 90/2.54 in = 35.43307087... in

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Estimate 80,767 - 37,291 by first rounding each number to the nearest thousand.
N76 [4]

Answer:

44000

Step-by-step explanation:

Given the following question:

80767-37291

To estimate by the nearest thousand, we have to look at the thousand's place value and then look at the number next to it, to see if it's greater than five.

80767-37291

80767

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81000-3700=44000

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Hope this helps.

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Which statements regarding the diagram Triangle EBC are true? Select three options
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Answer:

The answer would be:

B. ∠DEC is an exterior angle.

Step-by-step explanation: Your welcome

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A survey was conducted of 42 students who take math, Eng lish, or history. In the survey, 15 students said they take math and hi
strojnjashka [21]

Answer:

16 students take only English or only Math.

Step-by-step explanation:

We can solve this problem by treating these values as sets, and building the Venn Diagram.

I am going to say that:

A is the number of students who take Math.

B is the number of students who take English.

C is the number of students who take History.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only take Math, A \cap B is the number of students who take both Math and English, A \cap C is the number of students that take both Math and History, and A \cap B \cap C is the number of students that take all these classes.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

There were 42 students suveyed. This means that:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42

We start finding the values from the intersection of three sets.

12 students said they take math, English, and history. This means that:

A \cap B \cap C = 12

18 students said they take English and history. This also takes into account those who take math, english and history. So:

(B \cap C) + (A \cap B \cap C) = 18

B \cap C = 6

17 students said they take math and English.

(A \cap B) + (A \cap B \cap C) = 17

A \cap B = 5

15 students said they take math and history

(A \cap C) + (A \cap B \cap C) = 15

A \cap C = 3

2 students said they only take history.

c = 2

How many students take only English or only math?

This is a + b, that we can find by the following formula:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42

a + b + 2 + 5 + 3 + 6 + 12 = 42

a + b = 16

16 students take only English or only Math.

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