Solve for x in the equation p(m+qx)=rx+n

1 answer:

6 0

$p(m+qx)=rx+n\\\\\implies pm+pqx = rx+n\\\\\implies pqx-rx = n-pm\\\\\implies x(pq -r) = n-pm\\\\\implies x = \dfrac{n-pm}{pq-r}$

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Patrick raced round a 440 metre circular track and stopped suddenly after 900 metres . How far was she from the starting point a

castortr0y [4]

Answer:

20 meters

Step-by-step explanation:

The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.

So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.

The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be $900-880=20$ meters from the starting point.

8 0

3 years ago

PLEASE HELP Complete the table with the number of sit-ups you have to do sunday so that the mean number of sit-ups per day is 10

klemol [59]

The complete table will be:

$Monday - 100\\ Tuesday-65\\ Wednesday- 120\\ Thursday-150\\ Friday-90\\ Saturday- 0\\ Sunday-175$

Explanation

Suppose, the number of sit-ups in Sunday is $x$

Mean is the simple average of some numbers. For finding the mean number of sit-ups per day, we need to divide the 'total number of sit-ups' by the 'total number of days'.

Here the total number of days is 7 and the total number of sit-ups for 7 days $= 100+65+120+150+90+0+x= 525+x$