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Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer:
The volume of the cart will be 24 ft^3
Step-by-step explanation:
The first thing we need to calculate for this question is the number of boxes that fill the entire cart.
A layer of boxes consists of 8 boxes.
The cart holds a maximum of 3 layers of boxes.
So, the total number of boxes held by the cart are:
Total boxes = number of layers * boxes per layer
Total boxes = 3 * 8
Total boxes = 24
Since each box has a volume of one cubic foot, the total volume of the cart will be:
Volume of cart = number of boxes * volume of each box
Volume of cart = 24 * 1
Volume of cart = 24 ft^3
Given
81 red balls
Number of balls per row = Number of rows
Procedure
b = Number of balls
r = Number of rows
T = Total number of balls
b = r
![\begin{gathered} T=b\cdot r \\ Given\text{ b=r} \\ T=b^2 \\ b=\sqrt[]{T} \\ b=\sqrt[]{81} \\ b=9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20T%3Db%5Ccdot%20r%20%5C%5C%20Given%5Ctext%7B%20b%3Dr%7D%20%5C%5C%20T%3Db%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7BT%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B81%7D%20%5C%5C%20b%3D9%20%5Cend%7Bgathered%7D)
The answer is:
Number of rows = 9
Number of balls = 9
The circumference is 81.68 mm. C= 2pi(r)