A ball is thrown vertically upward from the ground. Its distance in feet from the ground in t seconds is s=−16t2+192t. After how
many seconds will the ball be 560 feet from the ground?
1 answer:
Answer:
t=7seconds or 5seconds
Step-by-step explanation:
s=-16t^2 +192t
let s=560ft
560=-16t^2 +192t
16t^2 -192t+560=0
16(t^2-12t+35)=0
(t^2 -12t +35)=0
factoring it ,it will give
(t-7)(t-5)=0
solving for t
t-7=0 or t-5=0
t=7s or t=5s
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