A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
where the first digit cannot be 0 or 1.
so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.
this means there are

possible numbers.
b.
consider the numbers which start with 911. There are

such numbers, since for the 4th, 5th, 6th and 7th digits we have 10 choices.
then we remove this number, from the one we found in a:
There are in total

numbers which don't start with 911.
Answer:
a.

b.7,990,000
Answer:

Step-by-step explanation:
refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

The factorial of an integer n is evaluated as;

Using this concept, the above expression can now be simplified as follows;

Therefore, the permutations of 5 items taken 3 at a time is 60.
The next expression,
refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

Therefore, the combinations of 6 items taken 4 at a time is 15.
The final step is to evaluate the product;
