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3 years ago

One number is 8 more than another num-

Mathematics

1 answer:

viktelen [127]3 years ago

3 0

The 2 numbers are 14 and 6. 14-6 = 8.
14 + 6 = 20

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The diagonal of a TV is 26 inches long. Assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact

Tema [17]

Hello,
let's assume a the width, b the heigth.

sin 30°=a/26=1/2==>a=26/2=13 (in)
cos 30°=b/26=√3/2==>b=26*√3 / 2=13√3≈22.51666.... (in)

4 0

3 years ago

What is the equation of the parabola in vertex form x^2+6x-y+3=0?

Igoryamba

Subtract 6x from both sides, then square root, and have parabola.

5 0

4 years ago

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Simplify (12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})(12a 5 −6a−10a 3 )−(10a−2a 5 −14a 4 ) . Write the answer in standard form

Katen [24]

Answer:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

Step-by-step explanation:

Given

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Required

Simplify

We have:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Open brackets

$12a^{5}-6a-10a^{3}-10a+2a^{5}+14a^{4}$

Collect like terms

$12a^{5}+2a^{5}+14a^{4}-10a^{3}-6a-10a$

$14a^{5}+14a^{4}-10a^{3}-16a$

Hence:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

6 0

3 years ago

Diagonals of parallelograms<br><br> Solve for x

Lunna [17]

Diagonals bisect each other

$\\ \bull\tt\longmapsto 2x+10=3x$

$\\ \bull\tt\longmapsto 3x-2x=10$

$\\ \bull\tt\longmapsto x=10$

Option B

3 0

3 years ago

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PLEASE HELP! I been stuck on this assignment for over 2 weeks. My teacher gave me a simple explanation when I asked for help, bu

loris [4]

Answer:

Question 1: x = 0,6,4

Step-by-step explanation:

#1. If we let x be the side of the cut-out square, the formula for the volume of the box is

$\text{Volume} = (12 - 2x)(8 - 2x)(x).$

Expanding gives us

$\text{Volume} = 4x^3 - 40x^2 + 96x.$

To find the zeros, we need to set the equation to 0, and the values of x that would result to zero would be:

$x = 0, 6, 4$

3 0

3 years ago

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