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olya-2409 [2.1K]
1 year ago
8

10. WEATHER On average, the circular eye of a hurricane is about 15 miles in diameter. Gale winds can affect an area up to 300 m

iles from the storm's center. A satellite photo of a hurricane's landfall showed the center of its eye on one coordinate system could be approximated by the point (80, 26).
a. Write an equation to represent a possible boundary of the hurricane's eye.

b. Write an equation to represent a possible boundary of the area affected by gale winds. ​
Mathematics
1 answer:
kykrilka [37]1 year ago
5 0

The equation to represent a possible boundary of the hurricane's eye is (x - 80)² + (y - 26)² = 7.5²

<h3>Circle Equation</h3>

The standard equation of a circle is given by:

(x - h)² + (y - k)² = r²

Where (h, k) is the center of the circle and r is the radius.

Given that diameter = 15 miles, hence radius = 15/2  = 7.5. Also, center = (80, 26)

The equation of circle is:

(x - 80)² + (y - 26)² = 7.5²

The equation to represent a possible boundary of the hurricane's eye is (x - 80)² + (y - 26)² = 7.5²

Find out more on Circle Equation at: brainly.com/question/1559324

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A jar contains 125 marbles. Given 5% of the marbles are green, 39% of the marbles are blue, and the rest are red, how many red m
scZoUnD [109]

Answer:

70

Step-by-step explanation:

39+5=44

100-44=56

56 percent of  125 is 70

4 0
2 years ago
Help and explain ///////////////////////////
Ilia_Sergeevich [38]

Hello,

First, you must understand that

(f-g)(x) means f(x)-g(x) it is the difference of two functions :

f(x)=2x+4 and g(x)=3x-7

f(5)=2*5+4=10+4=14

g(5)=3*5-7=15-7=8

So, (f-g)(5)= f(5)-g(5)=14-8<u>=6</u>

Answer A: none of the choices are correct.

An other way to do it:

(f-g)(x)=f(x)-g(x)=2x+4-(3x-7)= 2x-3x+4+7=-x+11

if x= 5 then (f-g)(5)=-5+11<u>=6</u>

4 0
2 years ago
Please help!! ill rate 5 and like!!​
Roman55 [17]

Answer:

2x < 5

2x/2 < 5/2

x < 5/2

x  ∈ ( -∞, 5/2 )

Step-by-step explanation:

5 0
2 years ago
Confused on this so please help:
scoray [572]

The equation p=4+3y is maximised at (4,5) and the maximised value is 31.

Given equation p=4x+3y and constraints x>0,x<4, y<5.

We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.

To find out the points we have to make graphs of the constraints first.

From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).

The above points are common points of graphs of all constraints.

The value of equations are as under:

At (0,0) , p=4*0+3*0=0

At (0,5), p=4*0+3*5=15

At (4,0),p=4*4+3*0=16

At (4,5),p=4*4+3*5=16+15=31

Maximum value of p is 31 and that is for (4,5).

Hence the equation is maximised at (4,5) and the maximum value is 31.

Learn more about equation at brainly.com/question/2972832

#SPJ4

4 0
1 year ago
Solve x+8y/4 =9y for x
MAVERICK [17]

Answer:

x = 28y

There you go:)

5 0
3 years ago
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